娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
:E|b/o#c~ pE&{a9K-fJJ
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
(@V"o)T,n A4o9X*] 3的12次方=531441 [/quote]O,lo axy[ |p o%e%V2^0z
^}o4YQ#O(KgU!V*Q
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
qj-\'J5} 1的32次方)c1}z*Iy-r8B(@

j?&U4X2g [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]#FW(SW;h q7Ws
n[#Ix c#bw(v:z"s
!]g6`U&s"hC
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
0?wy eQV,jW =13BFEFA65ABB83! h(e }-Gi@ VY-`q
=5559060566555523!
)y h$i3m8zh =您所要求的操作可能要花一段很長時間才能完成。9v[-^3av ej*Ik
=操作己取消
g\*`Z Fl(j{ ? u#Um;yDi
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:)@E+~_#a#Hn
Q$U dh6x:cR

&qa(g0B%Yj,P/bs3H n5l)u l{ d w&D
:(咁係一喎                 :giveup: [/quote]:ch o)WmF@&u Ata

4H o"OsI j 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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