娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
D M|9E9Ciw#H0AAu K/Z9HW WH
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:~%C4J^+Ae
3的12次方=531441 [/quote]+d8DEL._8J4i
h;Fd4W$I:j h!Pv
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
{e7xAFX5y 1的32次方KV)scecT

(Rq"w(M7R&a3p F [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
F @'D[DP:M
$Lvnm0Q8| ` q _go
z;p n8N_ :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
3BU A/z)t GK }:D%|J =13BFEFA65ABB83! h
u3Q+W)EB0} =5559060566555523!0J;Yb9~[.C
=您所要求的操作可能要花一段很長時間才能完成。
f4E5DTjx4Xq4L =操作己取消2wN0A y Wp0s)u
4~1O1AYs;k4O!u
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:%F5f~ZS3l(P

&P;Q&BTWQ4eyj.h
6t)Ku3E W~
r5Q"^r#E*]$~ :(咁係一喎                 :giveup: [/quote]+T\+R0F5A rHN
&X6G:@eK3}3m
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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