娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
E2[H.x4C\:C 6q(R S0P"?
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
,gA_v(Ow%x 3的12次方=531441 [/quote]
.rV/L;v!d3l o
8T hD X:v-j(U 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:'gJU |&U7st7X
1的32次方VSziPF Y
.F$f[&wh ORqt
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
5X1j[)_4Wu"g)`n DaGcj'h:w O8k

[B2`L(X A`;LX} :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! hHF6q#L/zd&SG#J,D
=13BFEFA65ABB83! h
5Os*rE9n8K3b/S =5559060566555523!
#U$K&?T7c*V{%^Bu =您所要求的操作可能要花一段很長時間才能完成。9@j a {u WF j$u
=操作己取消/mjE u8J0E

w3^|U J5]}F [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:OjL7f'?3xe0G&E `,X

1P~ IY)n:O%A yTYZ u!b}
g"E V e.i`cd
:(咁係一喎                 :giveup: [/quote]
r1N7j3A#? *[7LI#v7f
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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