娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
6\e.Trw:QrV
e"bD[5E.\| [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:"`2Sjqy
3的12次方=531441 [/quote]
U.z2Z%v2KHG"l3V
(u.])v!U? 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:2V[$G?}n
1的32次方eeZ)GWuy g"fH
h/Usvo@;Q#Rcw
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
%U$A$`*F:j"d s
Bp/jA C H2E Ifp7v
ZC SmI~ :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
N'y1aIR,r =13BFEFA65ABB83! h/U:e }O%dw_
=5559060566555523!
;L*I'N[YN5Y#fb =您所要求的操作可能要花一段很長時間才能完成。
O1m$E [C@)} =操作己取消
3Q1zS|L8tIjS \m j H;{T.| e2O$p-Mx
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:)A0k5H*n_IK~!F
x5`O3m{-]

E4_/c!U8u"i[:B7T )g#b#\ Z&_:~Znb
:(咁係一喎                 :giveup: [/quote]
d$STcF.R!C p)D&Lt1rLq
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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