娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
J0w[ k(H(R*G
:?"Eh~-n|k [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:{0f2V$\4s+@*rH
3的12次方=531441 [/quote]GP(|'uQ]ll

n(Mi^:QCNrP 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:(t#A ]cR \ j
1的32次方
[;K{lZm&a[
%H5m/E;E Rh [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
\BnCFo8@ l"g)w lV5I
p7Ta j'{J
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! hE IV)v(@r _
=13BFEFA65ABB83! h
j+My A2h+Ya =5559060566555523!
bt;g3Bg+q =您所要求的操作可能要花一段很長時間才能完成。
.b5z3n&W#P3Uj-n9w =操作己取消x:?} A bz6Hb

/m7_6j J~ORj [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM: bjRS;R GO^.}1m!J
b C-|+] P(i2hN-X
%X#KuA[h

+CzhB^T x Y T] :(咁係一喎                 :giveup: [/quote]
]MF*ae@
;Jz)LxYP4@;`| 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

頁: [1]

Powered by Discuz! Archiver 7.0.0  © 2001-2009 Comsenz Inc.