娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方J_[}hf9n ez:U
kBLH;Q%` L
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
!y(C q&}&gi` 3的12次方=531441 [/quote]}~7r m5lt?W

^:d@8x~)V3z[,i1w 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:,D3DD p0Vrj
1的32次方
FbM[+P.tW #`*Hf7w Vy Q1s
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
*Y+d(}s|Y D @kwJJtE-@S
/lZM JXZ*r$[ ~
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! hTOY`M,c;O"S
=13BFEFA65ABB83! h4K ^F y-`_8Q,^
=5559060566555523!
a(kT,O:Y*Q =您所要求的操作可能要花一段很長時間才能完成。(_4o#P,t'bjeM ?
=操作己取消
WH.d8N(lB dZ[:r&s7^'['r
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:6X s,L s(Q*S

7\ T|(v5m Ch
$}@5i4v2lok
tf c3h:U :(咁係一喎                 :giveup: [/quote]#i)oT)^)@0B R T/i

3rU2J*n0x8p2q&u 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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