娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方/k)H#] i hv xi
A's5W|(p
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:"n t F1bn[h Kk
3的12次方=531441 [/quote]
(? Vk+MDV;HGu(RF
8Jb9y!fKSd3c] 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:G*k7k2w;q(C$zG(s V4hc6[
1的32次方n-B[(\@q0R
e"P k'a6X&r3U0gh
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
M8VH9zWl7r U@6v
S4uT8z vw
J'V? q"n :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h9~-fQ$zeM
=13BFEFA65ABB83! h
,u&r5YA{fG)I| =5559060566555523!1gg;U D(V3~Zca ]
=您所要求的操作可能要花一段很長時間才能完成。
LyzX)AP_~ =操作己取消9i L,CYtC#H

!g!Cji7|~2xV*w [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
afd+i%v PH
c8b*V/I$Z%Iz 8bvjCJ7`
2Xr7A6R$~P
:(咁係一喎                 :giveup: [/quote]wD$Q"K`^ NIH8Hu

_f3dBN]&yH%z)F 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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