娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
_8FRk9fw$h^ZIz)C
9a.{c^'u y [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:2`6f.ko3N-CY/z [u
3的12次方=531441 [/quote]
#}^@8w8N9E;U _]qo.Q|B)T
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
O@E.E2A~t 1的32次方p%c"gJ/Z$r-C

K.X)jP#VsP$|+} [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]?Hjq~O Y
R6GOt\@*?

0DHs!ui :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
4Z9}t3eCOg3r =13BFEFA65ABB83! hD"Q`B#Wr
=5559060566555523!
$sf7q-mg0^BI@1G =您所要求的操作可能要花一段很長時間才能完成。3D*x U3y e Nl
=操作己取消u y?)JZsA

9w\:f$X)\l [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
`2K'|8Bp.Nu"O-C %_fUh5@|~!O
'ioH:O-u8rv.H4?Y

8ok"Ak'b :(咁係一喎                 :giveup: [/quote]:_Iu!_o

p5WP2h(Yn$p.N 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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