娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方Y-amj^U
.Kd A)q3DaFS*o
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM: fp{K&Snm
3的12次方=531441 [/quote]
"C'j N,~p} Nk
%Bx4`7fYkr@q 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
7|)GCN*Nys_+K 1的32次方 fi,O.iC

:P3r+m,p%q-H [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
4X+M$T(? @x
dZy B'z `"de1{.Mf o
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! hR,IRMe_ E
=13BFEFA65ABB83! h
ND [%dxm,iR xvM-B =5559060566555523!%k^%kYk"rB
=您所要求的操作可能要花一段很長時間才能完成。
$J+zPI&u-o =操作己取消
&CQ&y'tF4v}Vj
KpN4e9O e X)[.X [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
d}/[a%h0~ (_6?/h|O G!Q9]

9Sm}&OU0u Rqe6L /cu nWo
:(咁係一喎                 :giveup: [/quote]| [P3h d go3k

8g3Pby5v$s 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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