娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
&E*yu4r.tf,HA
ysCh;h$Y-}4p [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:zvgYhE%L$M/dm
3的12次方=531441 [/quote]
6zwD](T1I z3]Z[&o`*K[6_
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:3`(fm.T]H8K} ]
1的32次方sP_&w"Gw

pn&_5L.O j"MXk [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
:D6lq_+D)s,~,[$]y D"H#\%o![1u
`7dO!]%NrZ\
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h%Z@o#M(b9ea.d
=13BFEFA65ABB83! h
^;j]6[;wy9s6W+{ C =5559060566555523!
3b'{#X*e!H&aL =您所要求的操作可能要花一段很長時間才能完成。
&k,W-s}6D0l-w&Y[ =操作己取消
kt!g l(y$m^z_ U O1]h{8nS;F
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
T;v0@P-rs R7{+v"W/Ve

I*n:_|,u%L?ncT
-Hc;d!Gk SW :(咁係一喎                 :giveup: [/quote],G F)l-d@1gU

2y/O0fIg-l"a 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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