娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
?|:M-[`l;B
l g^%NB [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:e)c8z)z*a{V'G
3的12次方=531441 [/quote]
Zc {9w)cwx*N!X
'D n q#V:[1h5s| 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM: fcp-jY.p
1的32次方?!ehZf%xr?F
]&Wm7` b
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
7J*vo,];eu J{Mat ]4t0a!R}4i0G
$mA;SEwC@#[
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
#v-CEJ`T\ =13BFEFA65ABB83! h'V:dRqKe;RU'gF
=5559060566555523!
!`4rUI"s*D7a y!x =您所要求的操作可能要花一段很長時間才能完成。(y)|^f8~
=操作己取消k'e9P)^m;x9Tft

E)H [j+IUg5Y4F [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
-pyr?:zu hr
.}jL4jI'y;u"o 3Fk,T-I\ ]
9}o6E/S7X'O2q
:(咁係一喎                 :giveup: [/quote]FiX(K-T v

Ty(w4\)k8n^m 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

頁: [1]

Powered by Discuz! Archiver 7.0.0  © 2001-2009 Comsenz Inc.