娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
)n:a*h+_~:Wi8J
(b;d^'r2V G8? [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
? XODg,v MiS/C 3的12次方=531441 [/quote]
k%A*c!hoL 5gfhH1U`2?
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM: i\`_W_
1的32次方bj oR H9A[p.a
*yPZeN/[R`
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]-?,T-z~_%LI t#a

1F-u#vf/C
7P-Wgu#d5gaY6H :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
8v,L;n Kb$X =13BFEFA65ABB83! h,r0}4m`5iD/C l
=5559060566555523!Z!\^:W8ot6Xa
=您所要求的操作可能要花一段很長時間才能完成。
f9Z~G;]%~ =操作己取消
Wwr5JhM-Z @e-o1t;PmQ7Nr*in
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
.u!MYF G1L/tI
q:H#i!vL4a{Q
8i4}$r5T TQ
lsswUI :(咁係一喎                 :giveup: [/quote]#IcoF/e3lj

z8KTja B"P3M f yM[ 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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