娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
x2}C)w} N4n!RB g B ~r` sS
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:#H.i%B i0Bl
3的12次方=531441 [/quote]
v'Y$Ppj:~5} n Ixm,C4s7}-l3m
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:8D]g+r ]&_N-H
1的32次方e8viDh!cb2d

Q"~[Or*Y4qG@ [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
$u5Y%Em FZ8H)`'g
'xM(n;U;x1mMC b %|Sv2r-{)_#z
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h[T$N'w6Ga%]5Xy_
=13BFEFA65ABB83! h
U;Kh4VR$I+\` =5559060566555523!
)N5h.A:q"kw =您所要求的操作可能要花一段很長時間才能完成。
A(brO0x =操作己取消c#kg9n~}9^/{f
+z{/E b-p8~
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
b M+?~%Q"y^)Vsy
3\qxY*n
KI2rg4O9f6f)K8r"h
i^t9Qa C aY :(咁係一喎                 :giveup: [/quote]%K9IYA-r:BwN
`8? J3rgU!i
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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