娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
"nZgn8FMHAX*d *ClT|6w8Q7o
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
I ]J1?^og 3的12次方=531441 [/quote]
In3o!LyHI&f
5~K|o^uh 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:8Jok LE M
1的32次方
#s:h]#{&_ !C Q&g"W)Q%C [,?%V
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]pL#u"s1wUBV
`_9w C ^,}!|0N

p+Bq+y:a-P :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h{Nm e"W?)?p
=13BFEFA65ABB83! h A:P,a^av;Jf
=5559060566555523!
+O!K,~$nR =您所要求的操作可能要花一段很長時間才能完成。'z/]s-n^ ]
=操作己取消
6Vw%M)Z tzR/F
y5J:^(o5a#\BH7Z [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
.|mp.ty] OQjO R@YP/F*wG(}N

%e&gT\6K(b;o
!Uz`Vo u7W\4Iq :(咁係一喎                 :giveup: [/quote]'JNw({Ln
npt*h}
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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