娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方 k boM(_(gS
Zn"e.pd(c
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
9b_4fv1zA 3的12次方=531441 [/quote]k`^PZ;v*s
O9ZR7^&m dhv
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
$mF6G_$z*K 1的32次方,~3t7Q[4\?:BQs

9L;xB!D)^2B [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
"Y5N:STV*vj
;h f xX7A#bi
:@??vk{$YJ-ys :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
5gQ4lF[email protected] =13BFEFA65ABB83! h0@&EJ6[-M}/~ u@|%u$VJ
=5559060566555523!
*s U\_uv =您所要求的操作可能要花一段很長時間才能完成。
,QRAxR7~ =操作己取消
:?3I7[;u`p7E/[t
H d*q u)m:quh [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:7e3FcuA&Sq

I.T1J|k
^"}8c-[ @1\
}E$VEw :(咁係一喎                 :giveup: [/quote]
nbW!B.T t-@TC8Q6h3Wm z!?aRD7aJNRc,b&H
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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