娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方prSj.| m
%lU1~n N ?H.Xj Jg;A
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
u LZ'_myy 3的12次方=531441 [/quote]
5vE$j ~ g*?)I,sj Kvm$J([+}3~
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
E1S;F)VVHS 1的32次方
@ ^$u.@9`,vU@8R9?
{+RM7j4L$WHVXt [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]kyaf9h+}1T

x/_U _lY{h)]
H f sz/` H(yz#s :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
(m}AHD'k1j e =13BFEFA65ABB83! h)hD7[H9x^!{5b
=5559060566555523!
'g&A'l.}E6c G =您所要求的操作可能要花一段很長時間才能完成。_)`s\m9A W}L T4N
=操作己取消M'QM(DA!t[1]
`bs/}7Np-jX
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
g Dl+S Zy f)Bu8e%x9G)Y\

cck7r5zu
5p/]R,V_'Om2M)F+c,H :(咁係一喎                 :giveup: [/quote]
R$IO$o-A v'U'~4Oe:?h,U f,U
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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