playbr2 發表於 2007-3-2 03:34 AM
[size=5][color=Teal]在推理問題時,我們可以用 '' 如果/ if ''
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在 ''如果'' 之下有''如果'' .....一直至沒有''如果'' .....那就是真正答案
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但推理問題時,我們用 ''假設''
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那就會一直''假設''下去 , 但所得出來的答案 , 既不能證明''假設'' 之本身是否正確 ,它亦只是一個''假設'' 的答案 , if ''假設'' 有誤 , 那麼''錯誤''又豈能得出''正確''[/color][/size]
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[[i] Last edited by playbr2 on 2007-3-2 at 03:36 AM [/i]]
guswan 發表於 2007-3-2 04:42 AM
[size=6][color=Red]別偷看,最難是如何開始,一看就冇意義.雖然錯了:D[/color][/size]
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[[i] Last edited by Triangel on 2007-3-3 at 01:32 AM [/i]]
sakura310 發表於 2007-3-2 05:29 AM
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我己諗到點做
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但現在要返學><
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今晚又要同個索女慶祝生日><(好痛苦yo hoho~)
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play兄唔好咁快開工呀><
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等埋我返黎先呀~~
playbr2 發表於 2007-3-2 06:56 AM
[quote]Originally posted by [i]guswan[/i] at 2007-3-2 04:42 AM:
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如{A1,2,B1,2<>A3,4,B3,N(C)}T+,但是左邊重了,即A3,A4輕了或B1,B2重了: 所以: A3,B1<>A4,N(C)
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{A1,2,3,4<>B1,2,3,4}T- , {A1,2,B1,2<>A3,4,B3,N(C)},T+ , {A3,B1<>A4,N(C)},T- = A3(-)
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[color=Red]{A1,2,3,4<>B1,2,3,4}T- , {A1,2,B1,2<>A3,4,B3,N(C)},T+ , {A3,B1<>A4,N(C)},T+ = A4(-) [/color]
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{A1,2,3,4<>B1,2,3,4}T- , {A1,2,B1,2<>A3,4,B3,N(C)},T+, {A3,B1<>A4,N(C)},F =B2(+)
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[/quote]
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{A1,2,3,4<>B1,2,3,4}T- , [color=Green]( B1,2<>A3,4 T+ , 得知 B1 <> A4 T+ )[/color]
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{A1,2,B1,2<>A3,4,B3,N(C)},T+ , [color=Blue]代表A3,4,B1,2 有問題 ( B1,2<>A3,4 T+ , 得知 B1<>A4 T+ )[/color]
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{A3,B1<>A4,N(C)},T+ = A4(-) [color=Maroon]抽起了B2 , A3换了位 ,但天坪沒改变 , 代表B2 , A3 非問題波子 (得知 B1 <> A4 T+ ) [/color]
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那有問題的還有B1 , A4 ...... 那現在去看看B1 , A4 的歷史.
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[color=Blue]首先由 第二步知道 A3,4,B1,2 有問題 ( 亦得知 B1 <> A4 T+ )[/color]
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[color=Green]再由第一步資料( 亦可得知 B1 <> A4 T+ )[/color]
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最後如何下定論 {A3,[color=Maroon]B1[/color]<>[color=Maroon]A4[/color],N(C)},[color=Maroon]T+[/color] = [color=Red] A4(-) [/color]
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如果不是[color=Red]A4(-)[/color], 而一直是[color=Blue]B1(+) [/color]
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第一步 ( 得知 [color=Maroon]B1[/color] <>[color=Maroon] A4 T+[/color] ) ....成立
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第二步( 亦可得知 [color=Maroon]B1[/color] <> [color=Maroon]A4 T+[/color] ).....成立
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第三步(得知 B1 <> A4 T+ ) ......成立
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所以[color=Blue]B1(+) [/color]也是有可能的:good::good::good:
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[[i] Last edited by playbr2 on 2007-3-2 at 07:11 AM [/i]]
guswan 發表於 2007-3-2 07:10 AM
[quote]Originally posted by [i]playbr2[/i] at 2007-3-2 06:56:
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{A1,2,3,4<>B1,2,3,4}T... [/quote]
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對,我更正了,幫我看看仲有冇錯,累了
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[[i] Last edited by guswan on 2007-3-2 at 07:24 AM [/i]]
playbr2 發表於 2007-3-2 07:26 AM
[quote]Originally posted by [i]guswan[/i] at 2007-3-2 07:10 AM:
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對,我更正了,幫我看看仲有冇錯,累了
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[[i] Last edited by guswan on 2007-3-2 at 07:24 AM [/i]] [/quote]
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:haha:......:cry:
guswan 發表於 2007-3-2 07:26 AM
[quote]Originally posted by [i]playbr2[/i] at 2007-3-2 07:26:
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:haha:......:cry: [/quote]
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仲有錯?我好唔清醒啦!!定我清醒再睇番.
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[[i] Last edited by guswan on 2007-3-2 at 07:32 AM [/i]]
playbr2 發表於 2007-3-2 07:34 AM
[quote]Originally posted by [i]guswan[/i] at 2007-3-2 07:26 AM:
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仲有錯?我好唔清醒啦!!定我清醒再睇番.
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[[i] Last edited by guswan on 2007-3-2 at 07:32 AM [/i]] [/quote]
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如{A1,2,B1,2<>A3,4,B3,N(C)}T+,但是左邊重了,即A3,A4輕了或B1,B2重了: 所以: A3,B1<>A4,N(C)
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[color=Red]{A1,2,3,4<>B1,2,3,4}T- , {A1,2,B1,2<>A3,4,B3,N(C)},T+ , {A3,B2<>B1,N(C)},T- = A3(-) [/color]
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{A1,2,3,4<>B1,2,3,4}T- , {A1,2,B1,2<>A3,4,B3,N(C)},T+ , {A3,B2<>B1,N(C)},T+ = B2(+)
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{A1,2,3,4<>B1,2,3,4}T- , {A1,2,B1,2<>A3,4,B3,N(C)},T+, {A3,B2<>B1,N(C)},F =A4(-)
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[[i] Last edited by playbr2 on 2007-3-2 at 07:43 AM [/i]]
guswan 發表於 2007-3-3 12:20 AM
[size=5][color=Green]完原來人老了真係會變蠢,30歲果陣用咗37分鐘,
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如今......不過playplay 幫手checkcheck,我唔想check[/color]:D:D[/size]
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[b][size=6][color=Orange]Playbr2: 『恭喜guswan兄 首先通關 , 榮登狀元』[/color][/size][/b]
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**** Hidden Message *****;WXr8_!n/B
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[[i] Last edited by Triangel on 2007-3-3 at 01:23 AM [/i]]
guswan 發表於 2007-3-3 01:28 AM
[quote]Originally posted by [i]guswan[/i] at 2007-3-3 00:20:
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[size=5][color=Green]完原來人老了真... [/quote]
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#22最好hiden埋,因為雖然係錯,但原理一樣.
2000 發表於 2007-3-3 04:01 AM
[b][size=5][color=Orange]Playbr2:『恭喜 2000兄 成功通關 , 高中榜眼及第』[/color][/size][/b]
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[b]評語 : 此答案意念創新,方法大膽,乃大智若愚之作[/b]
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**** Hidden Message *****:dev:
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[[i] Last edited by Triangel on 2007-3-4 at 01:28 AM [/i]]
sakura310 發表於 2007-3-3 02:43 PM
PLAY兄,我仲未答,因為有野問,問清楚先答
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假如啦,我而家面前真係有13粒波子係度,咁在我開始操作前,我知唔知有問題粒係重左定輕左呢?
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我想清楚而家ge情況係邊種:
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(1)你俾13粒波子俾我,話俾我聽有一粒係重左,然後叫我搵出黎
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or你俾13粒波子俾我,話俾我聽有一粒係輕左,然後叫我搵出黎
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(2)你俾13粒波子我,話俾我聽,唔知佢輕左定重左,叫我搵出黎
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老實說,如果係開如操作前,我已經知佢係輕左or重左(但唔知邊粒係),我知道係一定可以做到的
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如果要透過3次操作,要在13粒波子中搵出一粒未知重左定輕左ge波子,我會說是不可能的
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但我見到又有人答到wor,雖然我沒有看他們的答案(所以我唔知係邊種情況,我估佢地答0岩掛...)
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所以我覺得係問題出在我身上,但又不能確定
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[[i] Last edited by sakura310 on 2007-3-3 at 05:22 PM [/i]]
guswan 發表於 2007-3-3 03:12 PM
[quote]Originally posted by [i]sakura310[/i] at 2007-3-3 14:43:
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PLAY兄,我仲未答,因為有野問,問清楚先... [/quote]
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唔知佢輕左定重左!!! 如果知輕重,還須要諗嗎?
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sakura兄,如果凡事一開始就存否定態度,
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而不嘗試探索一下,會自己局限了自己世界觀.
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試一試再想想才去否定還未遲.
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不過原來playplay個答案係好簡單,
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我鑽牛角尖了,我真蠢:cry:
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[[i] Last edited by guswan on 2007-3-3 at 03:25 PM [/i]]
sakura310 發表於 2007-3-3 03:27 PM
[quote]Originally posted by [i]guswan[/i] at 2007-3-3 03:12 PM:
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唔知佢輕左定重左!!! 如果知輕重,還... [/quote]
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咁係咪即係情況(2)?
guswan 發表於 2007-3-3 03:45 PM
[quote]Originally posted by [i]sakura310[/i] at 2007-3-3 15:27:
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咁係咪即係情況(2)? [/quote]
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情況(2),唔佢知輕左定重左.
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其實playplay係個問題度已經有好大提示,13粒同12粒大同小異,
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可以先諗下12粒點樣solve,
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我好耐以前諗過12粒,當時我用我自己嘅方法solve到,
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因為得唔得自己可以證實,所以一路冇睇過答案.
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亦冇再深入諗個原理,所以亦局限咗自己,
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而家知咗原理,就發現自己當時武斷地覺得太簡單了,是何其笨實.:D
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原來世界有幾大,在乎心胸有多寛敞:D
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[[i] Last edited by guswan on 2007-3-3 at 03:56 PM [/i]]
playbr2 發表於 2007-3-3 06:09 PM
[quote]Originally posted by [i]sakura310[/i] at 2007-3-3 03:27 PM:
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咁係咪即係情況(2)? [/quote]
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:agree::agree::agree:
大優勢 發表於 2007-3-3 06:22 PM
對不起
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我絕無講大話
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我三十秒已經破了
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(我用實物代替快啲)
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五個對五個
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之後
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二個對二個
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....方式
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所以其實有三種方法
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就係 3 4 5 都可以
playbr2 發表於 2007-3-3 07:06 PM
[quote]Originally posted by [i]大優勢[/i] at 2007-3-3 06:22 PM:
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對不起
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我絕無講大話
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我三十秒已... [/quote]
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吾係吾信你.......不過你要做條 formula 出黎 , 而條 formula 係要在所有变數之下都『萬試萬靈』,咁個答案先叫『完滿』
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比心機喇兄弟 :agree::agree:我會等你:good:
guswan 發表於 2007-3-3 11:33 PM
[quote]Originally posted by [i]大優勢[/i] at 2007-3-3 18:22:
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對不起
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我絕無講大話
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我三十秒已... [/quote]
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勁!!:good:
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請問五個對五個之後知道了什麼?:confused::confused::confused:
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選那二個對那二個?:confused::confused::confused:
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還有一次機會......剩下六個未知:confused::confused::confused:
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[[i] Last edited by guswan on 2007-3-3 at 11:35 PM [/i]]
sakura310 發表於 2007-3-4 08:16 AM
[quote]Originally posted by [i]guswan[/i] at 2007-3-3 11:33 PM:
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勁!!:good:
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請問五個對五個... [/quote]
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[b][size=5][color=Orange]Playbr2:『恭喜 sakura310 兄 成功通關 , 奪得探花』[/color][/size][/b]
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大家用n分鐘先諗到ge野,佢30秒諗到
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我諗佢個腦geCPU一定好高級,說不定到天才級數都未定= =
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