娛樂滿紛 26FUN's Archiver

SKII999 發表於 2008-1-17 07:26 PM

想問大家一條數,,

ab+bc-ac=0c_U3c V6AB
          a-c=101
!|+TqG Q8Pd1_           求b~R^R$qv"q2h

c*y_v(dAmx2o1\ n           要STEPS,,,THX

托迪仔T 發表於 2008-1-17 07:42 PM

a=101, b&c =0 :D

SKII999 發表於 2008-1-17 07:52 PM

我都知,,但唔知點得出個ans.,,anyway,,THX

ch.chak 發表於 2008-1-17 09:38 PM

a=101-c
8?3e4as#]W ab+bc-ac=0DK;T#h+}2K*i[)t
b(101-c)+bc-c(101-c)=0
F9H&s Kk;L!?/p 101c-bc+bc-101c+(c*c)=0
U:U jL \vo4wz c*c=0(e'gVo;Ln1G\
c=0
tZCi!S+i.lS4iL
3B@d0{:sO4Z a=101-0V6d9x(E!Pmr |^x
a=101
I9~;h3kz
!`.pH*Z ~2x {*P ab+bc-ac=02|1{&V-gX V1y
a=101
t5a;o2H$@1s2c c=0
&AU7H:zAleV 101b + 0*b - 101*0=0
(z7s*W{e ^ 101b=0CJ3XI'N5H+Q{
b=0

sakura310 發表於 2008-1-17 09:58 PM

[quote]Originally posted by [i]ch.chak[/i] at 2008-1-17 09:38 PM:$G4z'NN?[|w
a=101-cN%|g v&n b [@
ab+bc-ac=0;xL3g(k,|d-T
b(101-c)+bc-c(101-c)=0:O\.| K ^6Kz4G \
101c-bc+bc-101c+(c*c)=06E$N)J-D'HS
c*c=04v!N,p4rzh i
c=0
M v*SE1V h?S rf b!c]TdhW `2O Z'M
a=101-0$J ]R-x5W0Q;nT$H_
a=1017^jV8Qo\

y1eh ?BA.[ ab+bc-ac=0
k%UC/Il,?T.Q a=101
F})n%Xb D"D.vY c=0:ug PN&z.W A
101b + 0*b - 101*0=0
Pb{%seW)G2C 101b=0
9U7TK?^u\2a b=0 [/quote]
;UGI"jp@,TI T Fv5B'IdW!ZP,L
對不起
%Uj4Tb Kr9a 請容許我指出錯誤:_f SH"a4M\2s

M5?0DWS+PY5M 在一開頭
f(lSz5s IWq&j1LMy1L&z&]G
[color=Red]a=101-c[/color](原本是a-c=101,移項應該是a=101+c)
y kJ}c;X x ab+bc-ac=0.hy~@u8W
[color=Red]b[/color]([color=Red]101[/color]-c)+bc-c(101-c)=0
5m!a&y\O? [color=Red]101c[/color]-bc+bc-101c+(c*c)=0tAzz^(}
c*c=0nD4P)^b)U.p
c=0E Ul(PMPss9k$f.s
5X v%Je4SVR!c#] p
基於以上紅字的地方,其餘的地方我認為沒必要看了

ch.chak 發表於 2008-1-17 10:53 PM

[quote]Originally posted by [i]sakura310[/i] at 2008-1-17 09:58 PM:
X/u A^kt S*af
$\| M#^-XZVNb ~qt-Ij\
對不起
2CG d1Wv-s ?"H 請容許我指出錯誤
(l!Uw6fv (@&k_XH!I,@(r
在... [/quote]
y:H(AS;t a 係boAw E] @
冇留意錯左tim

呀俊 發表於 2008-1-17 11:00 PM

[quote]Originally posted by [i]托迪仔T[/i] at 2008-1-17 07:42 PM:"Ud8v/|EhY/zowa
a=101, b&c =0 :D [/quote]
;H(r iFKB ab+bc-ac=0$N3QP To2}7A kW m
          a-c=101bN9G}E:JC tM.ff
          求b
}6p*^#Yk(~E7u 咁玩法...如果c係-101...a同b=0 都得架wo:D

playbr2 發表於 2008-1-17 11:58 PM

[quote]Originally posted by [i]sakura310[/i] at  09:58 PM:
6S N]mZTd
)w.s'iq@Y 'l `$i%S9O1~rK
對不起'dz No t | S7_FL }/y
請容許我指出錯誤
d&x q5\c
mE'Iw'U} 在... [/quote]
%Oc(D_g { -SE v"h$D M#}o
咁你又吾去計;);):P:P

sakura310 發表於 2008-1-18 12:08 AM

[quote]Originally posted by [i]playbr2[/i] at 2008-1-17 11:58 PM:*{1QHcRan p.Ux

)te0py:I2v})L 6ty9M.kE
咁你又吾去計;);):P:P [/quote]
EpF0M3g9p+ehw B3t2v7Au jKH
playplay你串我?:mad::noway::fight::angry:(表情符號好好玩的說:D)%P T D@ m`s _'a

1n'f$Vz(Dfs 咁你呢~你又唔去計?:dev::dev:,V'\!H v*Q;|4H

OrI e2Ge-H w,m 等了這麼久也沒人貼答案出來
L K[6i"[F
r2N3}'qA:]f%Ve,l:K1i 那麼讓小生物來獻醜了:redface::redface::redface:
&m,{Jo7n,S%f7Z ]Y@.[)p&KdD
手寫關係,所以上傳圖片先了(懶得去打)X%{ipb&H
8H6On_ XJ6i:O'Tqz
由於題目沒有說到a,b和c是甚麼數,我暫且假設係整數黎做(光是實數的話...太沒意思了...) Ao#p+j7jN"vvJ4`)g

tw ` t(MQ\ 如果是實數的話,那麼請看到左邊2/3就可以了,中間和右邊是整數的解集(次序:左>中>右)
%EB#V!xX3f
&ZYOF,`mVN 用的不是甚麼古怪的方法,應該好易睇得明 oe8sQfUT

VFvoh,K/r 這算一種對付三個未知數,但只有兩式的求整數解方法.pQ`DZe)h B

TBY*? i 有不明的話可以提出:jCI)V%A

-O QszC(B%L 不過我要訓醒頭覺先回覆到,好累的說(脫力中...)
?i{0cl!y ["f2b;d+Q? k
[[i] Last edited by sakura310 on 2008-1-18 at 12:12 AM [/i]]

playbr2 發表於 2008-1-18 12:21 AM

[quote]Originally posted by [i]sakura310[/i] at  12:08 AM:n3x;gme.c U

'M*f1Uc}!N
e:D#j(C6E^4X~` playplay你串我?:mad::noway::fig... [/quote]
/{DM ?BVr r
~5PC-}#W4T;ZWZ({ 乜咁快手ㄚㄚㄚㄚ:D:D:D:D
*Z'i3]sa
B zs8h*m-@4t 個答案可以咁.....
{;rlYRp$x ` E"yN c-_BQa h6j
1.ab+bc-ac=0Wm6Jm;tm Y
a-c=1014T Qg9I'{ `4[ z%~l
b=ac/(a+c)=(101c+c^2)/(101+2c)xkit-M
設c=101n*Obp,[$i?/[9s`[Y
101n代入c o|6UV&e
FH sf#oJ9X
[101^2*n+(101n)^2]/(101+202n)
.p%hh8CWZ/o#Xn =[(101^2)n(n+1)]/[(101)(2n+1)]3r;P:`$t_:PT7c,Q
=[101n(n+1)]/(2n+1)
4w*S'i1g"f/S:qK
/M4wX d:`a;{P 因為a、b、c是正整數
v"Z$}$\ f!\#@6N 所以n是正整數
+t^A`u2c*e 所以[101n(n+1)]/(2n+1)是整數"C7H-mr g#F
2n+1=101(剩下的2n+1=n或2n+1=n+1,n沒有整數解)
KQj\$F!rT n=50
y+U+F|7f;T a=5151  <--a-c=101
;R9Q!p0VV V+s9\ b=2550  <--[101n(n+1)]/(2n+1)
\]q,T&?-k c=5050  <--c=101n| ^&d(b?0P#c
答案:b=2550

sakura310 發表於 2008-1-18 12:27 AM

Filename: DSC01158.JPGUJ K6O G.@%_&]Ed
Datetime | Downloaded by | Counts;bJ,n gX*y
2008-01-18 00:25:24 | 阿感 | 2
t5@qU)yJ }lS 2008-01-18 00:24:20 | playbr2 | 2
`\v6p(w,kqU 2008-01-18 00:22:02 | 但丁 | 2,I v&M tM:B+q)E:M E"e

;uVg;H _1W'F'{ 點解大家都down兩次? XD

playbr2 發表於 2008-1-18 12:30 AM

[quote]Originally posted by [i]sakura310[/i] at  12:27 AM:,papMtVj~.nA.~
Filename: DSC01158.JPG
'W!n7q&{p.|9C Datetime | Downloaded by | Counts.@0J~fz1c)Pa'jHU
2008-01-18 00:25:24 | 阿感 | 23NOSv|$A@
2008-01-18 00:24:20 | playbr2 | 2
u`9J_8P4Jm-M 2008-01-18 00:22:02 | 但丁 | 2
~ qOQ*j-P'V
S-P o,P@.[)~ { 點解大家都down兩次? XD [/quote]$t!@o/u4Yf

hDMf|G6kzx 我第一次開睇左2秒就close 左:P:P
4Ag"Hz G/z\#wr 之後DL (就变成第二次)

playbr2 發表於 2008-1-18 12:34 AM

[quote]Originally posted by [i]sakura310[/i] at  12:27 AM:
.bV8SCN"k6B Filename: DSC01158.JPG5Q ?/S(Gc ](^
Datetime | Downloaded by | Countst5~ ~Z Vqb
2008-01-18 00:25:24 | 阿感 | 2
yUg/Y-{ e.R 2008-01-18 00:24:20 | playbr2 | 2
U0[Sz^T1U 2008-01-18 00:22:02 | 但丁 | 2&}U%~ itg2a8^S

@tH(i8u 點解大家都down兩次? XD [/quote]
1}.Myc6w
^H{0gw 快d捉我錯處:D:D:D7S8AA_ n'P/[k
話吾定我都打錯 + - 符號
`ENy9XCg5Ar 係電腦打答案...的確幾煩...又哂時間...:giveup:

sakura310 發表於 2008-1-18 06:47 AM

捉錯處就唔敢當~2ZNfp ZtH w0VB
不過,c=101n哥度(解除n係正整數的限制,只是整數)!kPw%]#b`
就一下子限制左c一定要係101的倍數(好像看懸疑片,突然劇情說出一些事前沒提及過的線索,不爽~)
q d)|{@M 知道{101,0,0}和{5151,2550,5050}係答案的話,當然沒問題 V(s8X*Lj}}J
但原先是不知答案,所以唔知有無失根
vIz0u jRIJi.x s(XSxs
有時見到題目都感到有點不爽F @/i_HJC
題目所求的答案是整數,正整數,有理數,實數等等應該說清楚%\,H8}ELb8KZ
有些題目,整數解和正整數解分別好大的說,要找出整數解集有時可不是件易事= =

cutec 發表於 2008-1-18 08:26 AM

冇答案ga....
FRb ~ S?3@j (y;Mv6{w aD,U G
2條equation solve 唔到3個unknown ga....

Azuma 發表於 2008-1-18 08:56 AM

[quote]Originally posted by [i]cutec[/i] at 2008-1-18 08:26 AM:%s$z.V6Sf `M5@Z
冇答案ga....Th%s,e&j'F9S5v
xu2PJu#K
2條equation solve 唔到3個unknown ga.... [/quote]
cb1YV'h8I'jX _4XI)IaXM
agree "^&A7F+Z i
4ki'QDf ^cwo@ U
2 equations 2 unknows
5_dS)CEdm
LcSP#zq#_v if 3 unknows there should be 3 equations
j cB xl V,@$K l(W8~"Z2ihP
make it simple 4q2Bt)pB@~7hb2} _
@?R4O#N&RSH8Zt:q
say
$or:m#f!v(n| ] IL LX
a + b +c = 3eW1H/Y[bS#@!~h
+nr3zev0{Y
a+b = 2
Mf1eB4u2j
%tqS(~!IoF then c is 1 K t-t.S[I%P!e0|
PD nD^#i$HROtN
a = 2 - b 5S \4i9c nYO
3_5kK9XVip^
so 0 = 0 JC:g W0S3n\

g*tYW_E :giveup:

sakura310 發表於 2008-1-18 10:22 AM

[quote]Originally posted by [i]cutec[/i] at 2008-1-18 08:26 AM:
mSY#H6m%eP9Y 冇答案ga....u|5k@Uv N

H4U/[K7Js)@U 2條equation solve 唔到3個unknown ga.... [/quote],j%x(W e+G
mZv)CYo;h`
此言差矣~
c)P Q#_pcX'd'W
/aB*\:V)b5^d;Y]u0U 2條equation solve 唔到3個unknown ga
p'Om*F$XcwG.c9@#E 還欠一個條件,就是3條equation都是linear independent(線性無關)的EH8Pc+Mb*f;a
TTA&BS`F)U
簡單點說,多元一次方程就是線性方程的一個例子
8[#zc:[a.Or Y k'j0U 在這情況下,當然是想求n個未知數,至少要用n條線性無關的方程Mg3bzD3m D A

6m8s D9a-O3h1b 如果不是線性的話,有機會1條方程解3個未知數的(這不是每次都可以的啦~)4W4m F9|%G@
例如 x^2-2(x+8y)+17+4y^2+z^0.5=0 就只有唯一整數解
!s\7D-KC 有興趣就解解看:sleep:
z5RhB t:x&A 不懂的話就問playplay,佢會知答案:dev:

playbr2 發表於 2008-1-18 02:47 PM

[quote]Originally posted by [i]sakura310[/i] at  10:22 AM:Q6pxn8N
&k*@~5Rt!I
2pr/}lW2j C~
不懂的話就問playplay,佢會知答案[/quote]
_r?2Za.A+S/Y 0VJ g] Uz
:cry::giveup::giveup::giveup::giveup:

playbr2 發表於 2008-1-18 02:57 PM

[quote]Originally posted by [i]sakura310[/i] at  06:47 AM:
@S9y@.s3o-qd 捉錯處就唔敢當qK$t6v2bW[
不過,c=101n哥度(解... [/quote]
hF"zz1k7vV$f-[
)}k+`hE 都係睇餸食飯姐 , 無理由因為題目冇同你假設就下下大包圍架7I8~#k7z9u%B |O_
反而適當地調節一下 , 咁會理性好多
'k2ZU1rlq+^8}2i 就好似隻game 由12粒珠 加到13粒珠咁
JIjM4S'^;_ 當''堂''好玩哂:P:P:P
n b)^.p |:D T
;e7W$JA%W|PD p.s. 求''堂''字正寫:agree::giveup:

QuiGonJinn 發表於 2008-1-19 03:49 AM

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