娛樂滿紛 26FUN's Archiver

SKII999 發表於 2008-1-17 07:26 PM

想問大家一條數,,

ab+bc-ac=0pS H2em[C
          a-c=101
"i*Smuf;C           求b,Eh:K3e,fi-s

v!Q}E"qX0I           要STEPS,,,THX

托迪仔T 發表於 2008-1-17 07:42 PM

a=101, b&c =0 :D

SKII999 發表於 2008-1-17 07:52 PM

我都知,,但唔知點得出個ans.,,anyway,,THX

ch.chak 發表於 2008-1-17 09:38 PM

a=101-c\^o+y.j%_
ab+bc-ac=0
6H$Bb6RG0R*xK b(101-c)+bc-c(101-c)=0
!t1o[9s^(r 101c-bc+bc-101c+(c*c)=0X/`D*[zX0n
c*c=0^1E ]2N&T4L
c=0
7d3X^U h%R f&WL yk K0f7]NXS TMND
a=101-0
j fL%\7v$km a=101
Si p5K)o&s+jr
xeQu CS&D#?:G|i ab+bc-ac=0#U\.J'U4b)xJZ
a=1014b{]\!H.x-?0u
c=0
8mS+Je Ch u!^ 101b + 0*b - 101*0=0 wg{t!|b!iR
101b=0v7pd,\L_mmm$?8O@V
b=0

sakura310 發表於 2008-1-17 09:58 PM

[quote]Originally posted by [i]ch.chak[/i] at 2008-1-17 09:38 PM: T-l&t(F^;E^ lA2vm
a=101-c dqM3U)w ^#W
ab+bc-ac=0
gY]P&H$r'Da8E X;e b(101-c)+bc-c(101-c)=0
(`a$w:X,n 101c-bc+bc-101c+(c*c)=0
O-OyF `5x'V c*c=0
*CQc7k-Y;qI@Or c=0_2t"W8aGx~n6@
%_AIaB|'Am+b A
a=101-09G%s] p(S[.C7w
a=101 L}N(kZ(E

|3u}1i$~_B ab+bc-ac=0
%xB-D ^;zWq$l*{ a=101*NPv@ _S
c=0
O nc/H;X2M 101b + 0*b - 101*0=0Ch1R\y|h?ux+?}
101b=0
-z#Vj+_^Gx b=0 [/quote]GM#t[ y!M9Jy
.R,A3B%HX T J f
對不起yY.x ~t s-@;R$~
請容許我指出錯誤
A5}L5CG n.G No+ShG\$cB
在一開頭
4]A}4SnQb}&Ys
(n:p R*X8K;j(U [color=Red]a=101-c[/color](原本是a-c=101,移項應該是a=101+c)
c6R2|*QN q3e ab+bc-ac=08R)d8d3w7q [
[color=Red]b[/color]([color=Red]101[/color]-c)+bc-c(101-c)=0
Yk*U:~z6Q3UA [color=Red]101c[/color]-bc+bc-101c+(c*c)=0Z.A;Tp}QI7|
c*c=0.N E0e ]7c!h+NQ#BD
c=0
x.u0AKq7N /j7u_ZC [2t#g{,KJ
基於以上紅字的地方,其餘的地方我認為沒必要看了

ch.chak 發表於 2008-1-17 10:53 PM

[quote]Originally posted by [i]sakura310[/i] at 2008-1-17 09:58 PM:
a5i ?j%h?3\8cn 4]|"d"G u
+tH}/T5BTY
對不起
Zu7^du%I"W 請容許我指出錯誤
'Y6H|3Vu-zQ3k %K'Isf-q Q-P*l
在... [/quote]|;R5dkR!A F
係bo4wh LSR
冇留意錯左tim

呀俊 發表於 2008-1-17 11:00 PM

[quote]Originally posted by [i]托迪仔T[/i] at 2008-1-17 07:42 PM:
[7XXae Lw a=101, b&c =0 :D [/quote]xXw#vI,tw
ab+bc-ac=0~u1K|n8Z
          a-c=101
7h#m#iu,b&Z+A"B&G fK           求bQna.XR1e7h
咁玩法...如果c係-101...a同b=0 都得架wo:D

playbr2 發表於 2008-1-17 11:58 PM

[quote]Originally posted by [i]sakura310[/i] at  09:58 PM:G8V\pJp8E"}?I

q)F7s&|X9Xcy"ys
n{I\1e2ri$e4f 對不起
OMh| ~/l 請容許我指出錯誤
!ld.N4@;nx gt -ar |!_ `7M2J*mA_(W}
在... [/quote]1n/@/LQ:\&wxKD*]

@7P O3NB {3L-k1r 咁你又吾去計;);):P:P

sakura310 發表於 2008-1-18 12:08 AM

[quote]Originally posted by [i]playbr2[/i] at 2008-1-17 11:58 PM:)j1tBz/NIK

P a+s6u8i (G$b(w/R4Tkwx
咁你又吾去計;);):P:P [/quote]~"Jr P No9^ u

z"`%M8h(hd playplay你串我?:mad::noway::fight::angry:(表情符號好好玩的說:D)-T3Q3Hf-Bq"a

H,jZY_8?4X.T 咁你呢~你又唔去計?:dev::dev:O9lT$M9H"E*vZ
i'~;NviI3j2S"Z
等了這麼久也沒人貼答案出來+I/Rl&Q-KIH
`m+[8E&`P }o
那麼讓小生物來獻醜了:redface::redface::redface:Xf-b{$t)B b&{1?Py
'\O8v5CP+Ie W
手寫關係,所以上傳圖片先了(懶得去打)R`){o2P^5lxJ5B

&v0mF$Up 由於題目沒有說到a,b和c是甚麼數,我暫且假設係整數黎做(光是實數的話...太沒意思了...)
)nhg(Q B}cy!]j{ s*O G!tM._/l-w~Y
如果是實數的話,那麼請看到左邊2/3就可以了,中間和右邊是整數的解集(次序:左>中>右)X+_ y7B!w

P ?^:jL%^3SpU0R"T0b 用的不是甚麼古怪的方法,應該好易睇得明
E8KA n/w u_(OI)k[*}Cl
這算一種對付三個未知數,但只有兩式的求整數解方法{&D.G*I/^

,J.S6rN)g7K 有不明的話可以提出
%^Y HL:KMbf I%I0P"yO)A{)O
不過我要訓醒頭覺先回覆到,好累的說(脫力中...)&xv]weq^|

,M.u W Y)RF(f:z [[i] Last edited by sakura310 on 2008-1-18 at 12:12 AM [/i]]

playbr2 發表於 2008-1-18 12:21 AM

[quote]Originally posted by [i]sakura310[/i] at  12:08 AM:(@^fKO4Mr r

(|7uV fh!I
*a1V9B_3n{@%N*t playplay你串我?:mad::noway::fig... [/quote]
9sJq| u^V"a] v%G6|8ZE
乜咁快手ㄚㄚㄚㄚ:D:D:D:D
VM6amC AS/V Bvf,^hVq
個答案可以咁.....
;Eq1^3s+N.o4g9LC il5w:iB(t"X+k)b c
1.ab+bc-ac=0"XC(U/v7Wp2V
a-c=101
WBb8j$X#|rZ'~,R b=ac/(a+c)=(101c+c^2)/(101+2c)N;Giy S[0X
設c=101n
k;A)Dpq&P P4h 101n代入c
txBN0f1e.Z:@g e6TX6d%uN,q
[101^2*n+(101n)^2]/(101+202n)"[+{k%P,Z/@K
=[(101^2)n(n+1)]/[(101)(2n+1)]
-`+K}&p'D6he I =[101n(n+1)]/(2n+1),v0nN;j7oJc Z
,A#uZ0pC~%F ecL5F
因為a、b、c是正整數
o9`U+` V sv [;q 所以n是正整數4vx2K| ~#?9x2U!bB
所以[101n(n+1)]/(2n+1)是整數
+U@},c0` H 2n+1=101(剩下的2n+1=n或2n+1=n+1,n沒有整數解)N*aU/ALN%g"W3c!V6\
n=50}0Y1p_,A
a=5151  <--a-c=101
-Qmm p ] b=2550  <--[101n(n+1)]/(2n+1)
3_,NeF*S$Q,@ Q p;r6F c=5050  <--c=101n
k?){,w"SVpmT0c 答案:b=2550

sakura310 發表於 2008-1-18 12:27 AM

Filename: DSC01158.JPGR6P4yO*ZV
Datetime | Downloaded by | Counts
"y$~k9h%L5L 2008-01-18 00:25:24 | 阿感 | 24rt n2n}:`.~.O0^h
2008-01-18 00:24:20 | playbr2 | 2b"_*mH6b#i kE
2008-01-18 00:22:02 | 但丁 | 2
,t'wi%X5i{ UM*dje _'^6M
點解大家都down兩次? XD

playbr2 發表於 2008-1-18 12:30 AM

[quote]Originally posted by [i]sakura310[/i] at  12:27 AM:
{AiVoq Filename: DSC01158.JPG)L} k1w&F(B
Datetime | Downloaded by | Countsf*\|-a1XP2\
2008-01-18 00:25:24 | 阿感 | 2
(Q5Q-msd-F"f G1r1S 2008-01-18 00:24:20 | playbr2 | 2^J4J~a!H
2008-01-18 00:22:02 | 但丁 | 2R%r.`1j1[ _
*u1|um?9No
點解大家都down兩次? XD [/quote]
*y2N%S4Pw&B]9@
M2K4Y:[a 我第一次開睇左2秒就close 左:P:P
a}m)F/TQ 之後DL (就变成第二次)

playbr2 發表於 2008-1-18 12:34 AM

[quote]Originally posted by [i]sakura310[/i] at  12:27 AM:iQ$[8C#f;C c#D
Filename: DSC01158.JPGZc*tB5h3Y
Datetime | Downloaded by | Counts
@5pfuw0G 2008-01-18 00:25:24 | 阿感 | 2
5P9QJ?X/Su/?:C 2008-01-18 00:24:20 | playbr2 | 2#B^Qo)c2I;D7TK ~)GQ
2008-01-18 00:22:02 | 但丁 | 2r2ZZ/u+u"ylL
kl,VR2_?[Mz
點解大家都down兩次? XD [/quote] kY#{vF?*g0[0f K

mXl.g&w)y*RC 快d捉我錯處:D:D:D~I3A"f&i:s
話吾定我都打錯 + - 符號"^*?Oj2g/|(L
係電腦打答案...的確幾煩...又哂時間...:giveup:

sakura310 發表於 2008-1-18 06:47 AM

捉錯處就唔敢當
vKc_(};G]Y:X 不過,c=101n哥度(解除n係正整數的限制,只是整數)
L,s&BnV:J F 就一下子限制左c一定要係101的倍數(好像看懸疑片,突然劇情說出一些事前沒提及過的線索,不爽~)EXX)Yj&b
知道{101,0,0}和{5151,2550,5050}係答案的話,當然沒問題
2wxFIR6A"r:hm 但原先是不知答案,所以唔知有無失根
1J!j4`t(l|
dA*j3~8S 有時見到題目都感到有點不爽
+D }(aM"j;h!a7k"U;We g tV 題目所求的答案是整數,正整數,有理數,實數等等應該說清楚Q]i!@z
有些題目,整數解和正整數解分別好大的說,要找出整數解集有時可不是件易事= =

cutec 發表於 2008-1-18 08:26 AM

冇答案ga....
lK@2`!x P6I
6O @a.F ]N*] 2條equation solve 唔到3個unknown ga....

Azuma 發表於 2008-1-18 08:56 AM

[quote]Originally posted by [i]cutec[/i] at 2008-1-18 08:26 AM:lVx"O!~'kX:H
冇答案ga....kRm_ BxA!eC s
\dp7v(mX#k r+a z:h
2條equation solve 唔到3個unknown ga.... [/quote]
b)M jawqvD
8u.Utxa@3i%L agree (L~!I1M~T8v#i0ej

*y0v AO3j}4I#u 2 equations 2 unknows
$Iq0c.zB[9a+M 1_ CO/|y/b
if 3 unknows there should be 3 equations /H6`]-fpP7F9b!Z:L

6F#Lb*_e+^6z make it simple zoCo6N;aL
_[;o(w4@(N"aY&n x
say $[MbI\{D

-UI"_.n zB r@c a + b +c = 3
u*WR0i6r#K^
H xFph$q/H$C a+b = 2
6[NXnfkg kE;[y2P6n$o uS0P%oK*co!c,?
then c is 1
UF3Ca"wy M$ITi9I EK7U+W
a = 2 - b
d;L#w,`ht m+M 1JJv k*q
so 0 = 0 ZLLE"N} Z

KeZ@wL6Xb7k%|T :giveup:

sakura310 發表於 2008-1-18 10:22 AM

[quote]Originally posted by [i]cutec[/i] at 2008-1-18 08:26 AM:qJ9oca5N\uu{)D
冇答案ga....
#lc^0T*iU(|,d s |i f/SNM$OL
2條equation solve 唔到3個unknown ga.... [/quote]+V/W9Rzx

1],[3{,b;F6i 此言差矣~QB,l Z X,D~$Y/Y

-|4X9D&` dW+hy 2條equation solve 唔到3個unknown ga
z-{w TF^;N 還欠一個條件,就是3條equation都是linear independent(線性無關)的
hYb E,D Fu7[VE
!g!`P*xMT K 簡單點說,多元一次方程就是線性方程的一個例子
:v iY _M KT4`YB+G 在這情況下,當然是想求n個未知數,至少要用n條線性無關的方程f?fKOGF

,{9L O} gkF"D 如果不是線性的話,有機會1條方程解3個未知數的(這不是每次都可以的啦~);KMw1ad7pT2|\ i
例如 x^2-2(x+8y)+17+4y^2+z^0.5=0 就只有唯一整數解G&Dh%e nr
有興趣就解解看:sleep:
H+wa5jB!nHyc 不懂的話就問playplay,佢會知答案:dev:

playbr2 發表於 2008-1-18 02:47 PM

[quote]Originally posted by [i]sakura310[/i] at  10:22 AM:X^;G)Dko

'z;KT XH{ U"Ek$M~
eDp5u8C 不懂的話就問playplay,佢會知答案[/quote]
wO'g)E3` ~ \ @AWO)P0M5o
:cry::giveup::giveup::giveup::giveup:

playbr2 發表於 2008-1-18 02:57 PM

[quote]Originally posted by [i]sakura310[/i] at  06:47 AM: a m;I^jB'H,}\$E c2\
捉錯處就唔敢當
Y;E;v&U&w:wP 不過,c=101n哥度(解... [/quote]5J7LJ-[2a K
r#S+JfINNa"TWB
都係睇餸食飯姐 , 無理由因為題目冇同你假設就下下大包圍架
QtOM@ E 反而適當地調節一下 , 咁會理性好多
6e)GD mWP 就好似隻game 由12粒珠 加到13粒珠咁
!a P4L6me)fF 當''堂''好玩哂:P:P:PL;D/oKwT

eZbJP wj p.s. 求''堂''字正寫:agree::giveup:

QuiGonJinn 發表於 2008-1-19 03:49 AM

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