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Mikoyab 發表於 2005-3-27 02:30 AM

考你一個問題

請動動腦啊！

             Question:
             移動（不是交換哦）一個數字使下式成立:
             101-102=1
              Note: 運算符號不能動

[[i] Last edited by Mikoyab on 2005-3-27 at 02:39 AM [/i]]

pillgreen 發表於 2005-3-27 02:38 AM

101-(10x10)=1

axe 發表於 2005-3-27 05:47 PM

101=102-1

anttiniemi2000 發表於 2005-3-27 06:01 PM

move  means move to other position or cancel?

cymok3782 發表於 2005-3-27 08:34 PM

Q: 101-102=1
A: 102-101=1

exchange 1 and 2 'law'

pillgreen 發表於 2005-3-28 12:28 AM

[quote]Originally posted by [i]pillgreen[/i] at 2005-3-27 02:38 AM:
101-(10x10)=1 [/quote]
呢個先係真正答案！

[[i] Last edited by pillgreen on 2005-3-28 at 12:30 AM [/i]]

pillgreen 發表於 2005-3-28 12:28 AM

[quote]Originally posted by [i]pillgreen[/i] at 2005-3-27 02:38 AM:
101-(10x10)=1 [/quote]
呢個先係真正答案！

Mikoyab 發表於 2005-3-28 01:07 AM

[quote]Originally posted by [i]anttiniemi2000[/i] at 2005-3-27 06:01 PM:
move  means move to other position or cancel? [/quote]

move means move to another position. so, don't just cancel it.

blblblbl 發表於 2005-3-28 09:37 PM

[quote]Originally posted by [i]pillgreen[/i] at 2005-3-28 12:28 AM:

呢個先係真正答案！

[[i] Last edited by pillgreen on 2005-3-28 at 12:30 AM [/i]] [/quote]

This is introducing  new operator.

102 - 10 ^ 2 = 1 !!!

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