| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎6 }/ T8 f, Y2 w0 U0 L7 t0 @" E
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(x - a) = x - a3 r$ ^$ c* O+ L8 l/ u: Q' z1 c
(x - a) (x - b) = x^2 – ax – bx + ab
: H, F/ ]8 b+ M4 K$ B$ p. o/ P" e6 z(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc
" Y" v0 {8 P8 t& L8 p: [4 Y! L(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd5 c, M0 T5 J% E; J6 K6 f
如此種推，
0 G9 e$ ~- D6 t1 ^8 f: ]" t(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???
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8 ?1 f9 o' e9 N' i4 R" S[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

大大

點解你個問題好似有d問題
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Originally posted by Triangel at 2007-4-18 01:26 PM:) u  F! q; E: @+ {0 t- P
(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 – abx + acx + bcx - abc( a$ J: P+ K* T9 v
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- m3 c$ a* W8 d$ [( s% v3 ?[ Last edited by 大大 on 2007-4-18 at 01:54 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:
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[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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Thanks! 更正啦

littlenic

Originally posted by Triangel at 2007-4-18 01:26 PM:0 N! d! {5 _  a: p7 \/ ?& L$ g
第一個答中有獎
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(x - ...

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(x-x)= 0 ，所以答案係0，is it?

大大

Originally posted by littlenic at 2007-4-18 01:54 PM:
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& X. F0 V! D: q) h(x-x)= 0 ，所以答案係0，is it?

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唔似a.math題
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6 {- f  q- E  F5 ^+ S" K  i7 T2 Z[ Last edited by 大大 on 2007-4-18 at 01:57 PM ]

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:) B& G' S6 |7 u' s1 V2 k5 `
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7 T! E9 N2 Q  e(x-x)= 0 ，所以答案係0，is it?

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Bingo~

waikong

我係學校個學生會單張見過
* a5 r/ I! Q0 r1 t5 j. h6 q. o諗左一陣先諗到

playbr2

我吾識答啊http://i72.photobucket.com/albums/i162/xcopy/Monkey/049.gif~~~ http://i72.photobucket.com/albums/i162/xcopy/Monkey/022.gif

karen0123

(哭)~~~~~其實我都知係0.........3 g/ f2 Y8 G; @7 A0 D
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這條問題，貼落吹水版，名副其實
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5 b9 ^% y- l3 Y/ E[ Last edited by karen0123 on 2007-4-18 at 05:51 PM ]