| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎
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9 s" e8 m2 P$ b& x/ Y5 `(x - a) = x - a, T2 o# w/ B7 `3 a/ u4 T
(x - a) (x - b) = x^2 – ax – bx + ab. t8 I1 |4 o; f0 ]' R; I
(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc
6 f4 c6 i8 H; J/ j4 v1 _(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd
+ y6 d( i. T1 H+ K如此種推，
; o8 ?7 [  n; L# U3 _( A+ N(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???
3 u0 o8 U4 z( I5 b4 A+ x+ U( h( l. {/ ~, X. C
[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:
2 V% t- s2 }% j6 K咁難既=.=", Q& d( k3 I7 y& H3 s2 |

3 q/ s& K* q5 I. \# x; L[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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& Y8 B# @* k$ }, `2 v3 t+ @Thanks! 更正啦

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:
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(x-x)= 0 ，所以答案係0，is it?

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0 k  q. U( A4 `/ R, B- T$ FBingo~