| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎
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$ l# r& W! Q0 s5 k# c: `% g(x - a) = x - a
: i: Q0 R( p" ~2 {- C- G0 f(x - a) (x - b) = x^2 – ax – bx + ab
9 K( S4 b2 K0 m5 A: I4 i' c(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc( B+ j( B) Y( c. _) u& a' Q8 u
(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd9 F/ k% V3 s$ J  [4 i6 R2 S. i8 `
如此種推，( g  P" l5 H* I: a) {8 [- ]
(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???. T& _- f9 E- t; B0 ~5 h

% z/ J& ^1 {8 j; a. o( _7 M[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:) d2 }6 k. x5 u9 g
咁難既=.="
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0 ~4 b. S& Q# B1 Q! R' S[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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1 l1 |! V) \) s" I! B7 h$ XThanks! 更正啦

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:
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(x-x)= 0 ，所以答案係0，is it?

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2 k% j' b% W' x3 n9 p7 |Bingo~