eladmk

the question clearly said that "has to be more than half agree"

if only 4 and 5 left
5 will refuse to any offer then 4 will die and 5 gets all 100 diamonds
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if 3,4,5 left
4 must agree to any offer since he will die if 3 dies, so 3 will say 100,0,0 and 4 gets no diamonds but gets to stay alive
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if 2,3,4,5 left
2 can stay alive if at least three people agrees including him.  3 will disagree since if 2 dies he will get all the diamonds.  4 gets no diamond when 2 dies so if 2 give him something 4 will agree.  now for 5, if he disagrees and if 3 did pick 100,0,0 then he gets no diamond also.  for 2, he will say 98,0,1,1.  
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now 1,2,3,4,5
1 can say alive if at least three people agrees including him.  2 knows if 1 dies he can get most of the diamonds and 4 and 5 also know if 1 dies both can get a diamond, 3 will get nothing if 1 dies.  therefore if 1 say 95,0,1,2,2.  /// 1 will be safe for sure, he gets 4 votes.  BUT to maximize, 1 can say 96,0,0,2,2 then he will get 3 votes a bit risky though
///
my answer is 96,0,0,2,2

eladmk

everun said
如果我係5,我就認為最好1,2,3,4都死晒,
咁我就可以獨吞晒100%,
所以無論1,2,3,4肯分幾多俾我都好,
我都一定會投反對票~~
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that is in fact not true, when 1 and 2 dies, 3 gets to make decision and no matter what 3 says 4 will vote agree because if only 4 and 5 left 4 will die for sure.  So 3 will choose 100,0,0 and force 4 to vote agree (he gets to stay alive)  and 5 end up with nothing.

so 5's vote is very important when 1 and 2 is making decision.  Don't forget about him


by the way, my answer is still 96,0,0,2,2  =P

eladmk

1) If its what WooWoo said "所以正確應該係起碼半數通過。即係話如果有五個人﹐就要有三個贊成。四個人就要有兩個贊成﹐如此類推。" then my answer will be 96,0,0,1,3

2) If  it has to be over 50% vote, then my answer is 96,0,0,2,2

eladmk

oh yeah, i think terence323 is right, I forgot to take account of what C thinks.
so 97,0,1,2,0 is a better answer for over 50% vote.

The answer for 起碼半數通過 is 98,0,0,2 when four people left, then for 5 people, using terence's way, give number 3 and 4 a diamond and don't give number 5 anything, he will still get 3-2 vote, so the answer of 起碼半數通過 should be 98, 0,1,1,0

eladmk

James question:
這是一條很舊的IQ問題但都幾得意架﹐大家不妨試試:
有個迷路的冒險者﹐行到兩個門既前面﹐其中一個門會為他帶來出路使他可以獲救﹐另外一個會令他馬上喪命。他唯一的線索就是門前面的兩個人。一個只講真話﹐另外一個只講假話。拒地彼此都知道誰在講真話或假話。唯獨是只有可憐的冒險者分不出來。
這個冒險者只有一次問他們的機會。而這兩個人都會根據自己既本性而作出回應。SO﹐如果你是冒險者﹐你會點樣問而令到自己搵出"生路之門"呢?

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Let the two guys there be A and B.Then I will pick one of them, and ask "If you are the other person, which road will lead me to safety?"

for example, if I talk to B, i will ask him "If you are A, what road will lead me to safety?"

Wait til he picks a road, then YOU GO TO THE ROAD THAT HE DIDN'T PICK, that road will lead you to safety.

eladmk

actually for the diamond question, i do have a totally different approach.
if the answer is either A97, B0, C1, D2, E0
OR  A97, B0, C1, D0, E2.  D and E knows that they only can get 2 diamonds and D gets nothing at all!  So if D and E are smart, i say they will work together! since if they vote no all the way to the end, they will split the diamonds 50 50 each.  so my approach is as follows
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D,E  (50,50)
C,D,E (49,0,51)  or (49,51,0) 1 diamond should be enough to break the team.
//
Then if B is in charge, there is no way he can top C's offer so B dies for sure if he is in charge.  Therefor B has to vote whatever A's plan is.
//A can split the diamond this way, 48,0,0,52,0 or 48,0,0,0,52.  A will vote yes, B will vote yes because he wants to stay alive, and whoever gets 52 diamonds (D or E) will vote yes since he is getting more from this deal and it is enough to betray the other person.

eladmk

Thanks yuen122 for the support. =P

eladmk

For terence's coca cola question, my answer is
have 1 of the guy pour the coca cola to the cup until he thinks that it is enough for him.  Then GIVE the cup to the 2nd guy to drink and the 1st guy drink from the bottle!  Then should be okay