娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
is'G ~ k RT+J ,zz`1J(|$b
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
$mL%}:d)iF5? 3的12次方=531441 [/quote](c(J.G X+u#[1m Iyz

w"v,yQ3m*m 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:+\v:EU J5b$L&Ym
1的32次方
I g,Rb6}8H?&dlU e)U%`J g\v&u `
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
O0[kw}@~WdsV
3D j0V-Ui0H~
?dpV(m4w7WH :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! hx P!x/I ]7H
=13BFEFA65ABB83! h
i'{({zM9T$iS? =5559060566555523!
n&u*~3Jp B =您所要求的操作可能要花一段很長時間才能完成。u cCe:D2~1P1m.k
=操作己取消
u,Cmq^-SJ!n({1s
;z+pl4nO)y [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
cChSCqr x JG/BO} {C

u SH uu3G(L'Sk 0C^*[+v2q0q| k-C
:(咁係一喎                 :giveup: [/quote]
7RJ]N'nR.O R
w k7A?/n1TA&U 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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