娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方:H~#w I(V`5}
yX\*Q[:I*A%t
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:F]w2K)Y5{d}
3的12次方=531441 [/quote]
[i+q2p&t$CR
(Q;s x1pK.yDHT/^ 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:J S#B^O}f-l
1的32次方 Ni)G.b Fd
{n#{zvA-z
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
%w8b L)f(ltOM
&]!k/^-C.M$k9\ .TXBxT1~
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
(^%ZJ Ubo C =13BFEFA65ABB83! h&w)O-?'Fh
=5559060566555523! | [eaH#R [
=您所要求的操作可能要花一段很長時間才能完成。
*?d3mt0fnP-Z =操作己取消O UU9^#O/U

K9N*Drq/j i8j8l [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
b ue6TJQ "Y/\ V_bk@Dy

#W ~x.hz.E,] ya4r2mdma&]Ak
:(咁係一喎                 :giveup: [/quote]Gu Ey?7}8r

"_9^Dt{5[H N[lN | 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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