娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方R-~CEg+F3YZ Gz `

SRb(` GSB(\L D#G [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
aM}'Q,Wb 3的12次方=531441 [/quote]z;@"S[}Z
L1W3P7z"YI
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:
uk-@'w%_0@R 1的32次方
:P:J8dhl0w q OU`N7B2AzpR t
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
;n+g-Fj;~"n
*Za E~/O5uH ri8Jk ;dO(v5e_$` mJG
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
'F,pC-JA&~'WFL =13BFEFA65ABB83! h)oXs h wF h t
=5559060566555523!
+zI e h;{*|`/H =您所要求的操作可能要花一段很長時間才能完成。}0Kr$~ L
=操作己取消
,@1Nf,TL/j:{z5qB` C;X
u#yh nq;p"s'W8K [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:$}h&J9N,y/_!x

Q"PGk [i2T n6r` e/JI |n

(w"w,g9@3I :(咁係一喎                 :giveup: [/quote]AOyKt*wz}/c
Fk Fd+pyi3w8f
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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