娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方"twrNYP^

R3r6~zGo8dZ [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:xDo]k0R
3的12次方=531441 [/quote]5s*~ M7F)Nr%o

5TAF}9vO1JaJ 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:~$u v;{&Jqr}
1的32次方
8z"c4w(z]
&J3f$S [;@ h$iW [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]"T}4d:j*L4u@4wx

J$|%r Te{d? b
@8T/Fbf.O[T2V :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h
m$m3b Z"y7b.h'P =13BFEFA65ABB83! h
!z8AcXFF+`fZly{ T =5559060566555523!^IQ!\ORA$g!v
=您所要求的操作可能要花一段很長時間才能完成。5bZX mt/]+H-B'Y/S
=操作己取消
?Jp&i3^+@#J
,h7s%B!_&S,og [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:%jF,e]gj ^3i

_"D6w-z pUs 9Di%U]d2Ur
"X+InC#|2sz
:(咁係一喎                 :giveup: [/quote]
"x z1Wp-f5k X
Z Z+Wb[7\ 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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