娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方
p1afw*a W]3N
U2y ^ r:U3D b [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:
0{a7A[A PNV| 3的12次方=531441 [/quote]K:wU){wm

fKR0D|;H ?t*h|\'VQQ 都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM: uD \9XY;C
1的32次方
I9j S DZ"P|8Z?-x_
^[!}8aW{f p [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
-Y qpT/|'{ w
o6X\"nJ L;ac
g/XU n.\ A8Qm? :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! hS$GuVP3\ r#G
=13BFEFA65ABB83! h}'x4@a3D
=5559060566555523!
!Hn6C6d_1c7Ho =您所要求的操作可能要花一段很長時間才能完成。
B9bU)^ h ye2N4N =操作己取消
t0c wI!D[tvS!| kZrD4X)?[x!?l
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:R&bA4f/r"U {

F)af \#t,z*X1^t `:_ D5kZ*rW;}.~W`
2W O.D2B4d~ NL0g
:(咁係一喎                 :giveup: [/quote]
"r&n*Nn [Va7O 7OXAv XXX3PnN0x
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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