娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方1g0?_l7E6Dj
@$sKIsG-P!o
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM::Q)uz'\ pY"[
3的12次方=531441 [/quote]
vlB!T y*i n9vl(P&I*Wx_
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM:0[W/kvic Y
1的32次方t9[SUsF
[3a5j"E+Q foz
[[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
t`,UR1r){5N iNT8Bw
+t9S FgE8eoH x.S Gkd)C|$a9O
:(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h7?U,p6^,F
=13BFEFA65ABB83! hh7d8PDcD(A0w
=5559060566555523! `9tyE-c-[1_RL
=您所要求的操作可能要花一段很長時間才能完成。5\~"l'i X"^+|N2o6x
=操作己取消
]-UYko
3Df1P0u_:Po7q D [[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:t#Sdc b3N'k
!k5k ` g~-Y

5jnyn$fAUV;J -l-Pk:J0ij jz
:(咁係一喎                 :giveup: [/quote] E(y:NVs ?R
W)bL)~j J%BvVc
哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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