娛樂滿紛 26FUN's Archiver

^^優之良品 發表於 2007-2-2 10:28 PM

最大的數值?

利用1,2,3三個數字,如何組成最大的數值??

iamkaka 發表於 2007-2-2 10:51 PM

你真係問定iq題-.-?

singleung1956 發表於 2007-2-2 10:54 PM

3的12次方=531441

hlf 發表於 2007-2-2 11:02 PM

1的32次方2vyP(JQ6rxy

luk w(i [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]]

陳靖仇 發表於 2007-2-2 11:04 PM

[quote]Originally posted by [i]singleung1956[/i] at 2007-2-2 10:54 PM:&y?k,c5e,n l&b [/j-\a5a
3的12次方=531441 [/quote]
Gq~.hXA N Qi,JC ,r!I!Rv&gT"wO5~
都可以係, 3的21次方, 佢冇講過要順序

rongol 發表於 2007-2-2 11:20 PM

2嘅31次方

大優勢 發表於 2007-2-2 11:29 PM

[quote]Originally posted by [i]hlf[/i] at 2007-2-2 11:02 PM: I.L0u@8\Nd
1的32次方
$^@Q1y vpC
rdt1StP+d[!u [[i] Last edited by hlf on 2007-2-2 at 11:04 PM [/i]] [/quote]
L(GF8hS;{
7M4|E4sVj
:XS;tD` :(咁係一喎                 :giveup:

iamkaka 發表於 2007-2-2 11:32 PM

3既21次方

chuchu14 發表於 2007-2-2 11:43 PM

any  operator allowed?

hold_find 發表於 2007-2-3 12:18 AM

(3^21)! h"W;nVkZ["BNsZ6LE
=13BFEFA65ABB83! h@#e:T G+i
=5559060566555523!9U.FE.RU:u
=您所要求的操作可能要花一段很長時間才能完成。
i#Vu[;\u3NeT =操作己取消
w5_WWr(L )CV-^*L+Z,gb
[[i] Last edited by hold_find on 2007-2-3 at 12:24 AM [/i]]

Dan.elf 發表於 2007-2-3 02:02 AM

wow! Very "sum" ar!

specificness 發表於 2007-2-3 09:26 AM

[quote]Originally posted by [i]大優勢[/i] at 2007-2-2 11:29 PM:
7E9] _(FUn BzDZ2F}

b3D(K^@#[
?)}!cT]e'U&JT :(咁係一喎                 :giveup: [/quote]
L:j7A9T8m
yQ/a,K,pb0P 哈哈哈哈哈……搞笑:D:D:D

Killer111 發表於 2007-2-3 01:27 PM

答案會唔會就係321咁簡單呢?

karen0123 發表於 2007-2-5 05:02 PM

咁我又問大家,1,2,3,4四個數字點樣令佢地變到最大?

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