娛樂滿紛 26FUN's Archiver

SKII999 發表於 2008-1-17 07:26 PM

想問大家一條數,,

ab+bc-ac=0C5U,ED+fS$e|9y
          a-c=101
N2sQNms1J-M-m           求b8]9{KdQ*t%Rz$za\
l1mY9p)S5Gl0{!p
          要STEPS,,,THX

托迪仔T 發表於 2008-1-17 07:42 PM

a=101, b&c =0 :D

SKII999 發表於 2008-1-17 07:52 PM

我都知,,但唔知點得出個ans.,,anyway,,THX

ch.chak 發表於 2008-1-17 09:38 PM

a=101-cP1C#zr?E Im
ab+bc-ac=04`Pp2|_1T,hy7C n-eQs
b(101-c)+bc-c(101-c)=0
]N$]J+Ec B 101c-bc+bc-101c+(c*c)=0K8l0I0XPfTm{
c*c=0pKCy @Cs#xZ,h E
c=0
Qp _b Ex9q Eb*E|NYy^
a=101-0
__g&aT,z,{ a=101
&YJ[%C0R#B$O #g9? ktE
ab+bc-ac=0$HG$P:}vaw\
a=101
GK"v}2Yn!G3C c=0Q+J-_X Y7CDj
101b + 0*b - 101*0=0
%d&~&r \K!R3XJ8]4F 101b=0d O(YOS8f5st
b=0

sakura310 發表於 2008-1-17 09:58 PM

[quote]Originally posted by [i]ch.chak[/i] at 2008-1-17 09:38 PM:
]2w(__r,ME*P s;i a=101-cf }}N0C/_jZ.n
ab+bc-ac=0
6x{)Yv c8a*F#B7]g7y b(101-c)+bc-c(101-c)=0
R/[/r1lWPe\G3t1\ 101c-bc+bc-101c+(c*c)=0
d{)t.`o9B+CR c*c=0 ]8}$aMt
c=0Qka#Dsj*[1x
(s2X(O'C sm
a=101-0:Lni q0w7E3Aj
a=101
:L4N\k5`wO)R;k 7t0e^3? w|!i8K(m
ab+bc-ac=0
m4QL B@q T a=101
)`&N)k;Z!t c=0'H#gA\2bS%H#L;v6b
101b + 0*b - 101*0=0
P;_4Z@"O 101b=01SSs@^"],DcK.F/p
b=0 [/quote] ni%`dPU6x
0a{yt{%GU2J uV~
對不起
$V&w:H"[A7Bp/UeS}] 請容許我指出錯誤:}%U V Wt K

pvr(T@J-Wt 在一開頭4B|@AS Qp

4['S t(lHg [color=Red]a=101-c[/color](原本是a-c=101,移項應該是a=101+c)
$Xs ]gH4U}-}4D ab+bc-ac=0
L(I5g/[8c(V,C [color=Red]b[/color]([color=Red]101[/color]-c)+bc-c(101-c)=0/E2|-L9rZ\J:F
[color=Red]101c[/color]-bc+bc-101c+(c*c)=0
l-v;^y"q Y c*c=0 hZ4shT\
c=0%o5T'ji(b'hOr

;r+M.Qz;i(c g QK!b| 基於以上紅字的地方,其餘的地方我認為沒必要看了

ch.chak 發表於 2008-1-17 10:53 PM

[quote]Originally posted by [i]sakura310[/i] at 2008-1-17 09:58 PM:OGP%e.dw;_0D
PI-q"j/n8t JX/p_fB
D3`I(B$K4Y1f ug IJ
對不起
s*b1A$M9T Nt?9Q\l 請容許我指出錯誤(r5e1D$dv:Vq!@
(I1Wm7h-E/p$_G
在... [/quote]
gJ7A B HQ'E3f4e 係bo
)w|qVa,~o 冇留意錯左tim

呀俊 發表於 2008-1-17 11:00 PM

[quote]Originally posted by [i]托迪仔T[/i] at 2008-1-17 07:42 PM: a)Q+i s*`*G2c.j
a=101, b&c =0 :D [/quote]
c.e_Lp.h ab+bc-ac=0
`|7\s;|W           a-c=101&H!d4t9m:q_sJ
          求b
+cESW~~9P 咁玩法...如果c係-101...a同b=0 都得架wo:D

playbr2 發表於 2008-1-17 11:58 PM

[quote]Originally posted by [i]sakura310[/i] at  09:58 PM:ka2OK3i#M

D*pY S/f 6@"\TC Sb.{
對不起
I6})u6N+`;V1e 請容許我指出錯誤
Av0SZ8mSTg,~
%G V;G0ca-L6r 在... [/quote]f$s!nYl4~ `,S gB1C
)W,JL%W3]:C:n
咁你又吾去計;);):P:P

sakura310 發表於 2008-1-18 12:08 AM

[quote]Originally posted by [i]playbr2[/i] at 2008-1-17 11:58 PM:
i}p'dHD.b*j uo
s.f2Ah9frv&Z
} fi Z2^]rH 咁你又吾去計;);):P:P [/quote]
+n2_ q3dmk .|R2jv(F:d
playplay你串我?:mad::noway::fight::angry:(表情符號好好玩的說:D)
Db5J?p;p ,oA['ZB
咁你呢~你又唔去計?:dev::dev:
2E+m _ha$V3M
4w$_D[|J0{PQ 等了這麼久也沒人貼答案出來 | \q(Q;ci@,m)Y
'g`,f&fK+K9iK
那麼讓小生物來獻醜了:redface::redface::redface:
6V P~cy)K!_ S
a an c_*Lk 手寫關係,所以上傳圖片先了(懶得去打)
0Q$t7qF&D| C C1z/g0[ CMzHo
由於題目沒有說到a,b和c是甚麼數,我暫且假設係整數黎做(光是實數的話...太沒意思了...)
1}@ s Bz:w ot
CI+YOo C,b4T 如果是實數的話,那麼請看到左邊2/3就可以了,中間和右邊是整數的解集(次序:左>中>右)
c B9t A f S [ FL9b5I)ek)z
用的不是甚麼古怪的方法,應該好易睇得明
9tUQ*Zf #F9n^,^"Zu
這算一種對付三個未知數,但只有兩式的求整數解方法r$T4S9f|0k$v
np/d(K7k9N5O+X
有不明的話可以提出
"gIh s5ptAO O
#D.ND2ri 不過我要訓醒頭覺先回覆到,好累的說(脫力中...)
'tTi$}N ^/^u 1r$\ W R@2B2h J
[[i] Last edited by sakura310 on 2008-1-18 at 12:12 AM [/i]]

playbr2 發表於 2008-1-18 12:21 AM

[quote]Originally posted by [i]sakura310[/i] at  12:08 AM:6D)?p[(VpV

3s!@?[dsG@R
3Q-u5aT(}8]? N playplay你串我?:mad::noway::fig... [/quote]
(T:TI7BX 9Epw7s u } }
乜咁快手ㄚㄚㄚㄚ:D:D:D:D
|9at^9V&iB| } 1YD\7|+}_9?
個答案可以咁.....
F R{(TR,Uz%S$N
;]7mY7n;` 1.ab+bc-ac=0
$UL8V"F%j5~.J1w8e a-c=101
k8@0`@{x*E1] b=ac/(a+c)=(101c+c^2)/(101+2c)7f6f0Vw!n(Y5z
設c=101n
.u.`"Z ^9}L:Yd 101n代入c
Ux^D)E&dF!h
*N b2l~v(X)b [101^2*n+(101n)^2]/(101+202n)#FAh]h'{ _
=[(101^2)n(n+1)]/[(101)(2n+1)]
a"Ms/nj'q+i =[101n(n+1)]/(2n+1)5Yj"d*z|"[-W
4_+~ KMc
因為a、b、c是正整數
5n4i2gXI o 所以n是正整數
cW!U6UBy^3[B 所以[101n(n+1)]/(2n+1)是整數
D0X/ss;c S(t/v7}5Yd 2n+1=101(剩下的2n+1=n或2n+1=n+1,n沒有整數解)aL2S yJ*_K
n=50
f{,k+zY6Ka a=5151  <--a-c=101g)zt0w|$Ip
b=2550  <--[101n(n+1)]/(2n+1)
|)k+^;j p6P D+E c=5050  <--c=101n
%Q9xh_GU^ 答案:b=2550

sakura310 發表於 2008-1-18 12:27 AM

Filename: DSC01158.JPG
g"B?hr8|rf0QJ o5d Datetime | Downloaded by | Countsy^ L/?)TcL?
2008-01-18 00:25:24 | 阿感 | 2K o2yUt,?o0X
2008-01-18 00:24:20 | playbr2 | 2.a+}gdkc
2008-01-18 00:22:02 | 但丁 | 2
7y BTP+A5E2^ Qg S]9c_yr[
點解大家都down兩次? XD

playbr2 發表於 2008-1-18 12:30 AM

[quote]Originally posted by [i]sakura310[/i] at  12:27 AM: qHi,q{ OaH
Filename: DSC01158.JPG_3]i}F:\f
Datetime | Downloaded by | Counts
.laQd v7{7X 2008-01-18 00:25:24 | 阿感 | 2
W$s @x$O 2008-01-18 00:24:20 | playbr2 | 2
F"x*m0AV 2008-01-18 00:22:02 | 但丁 | 2
L:M ^*Cv.b;]&l6g
X5?'a5u n#q#`^k 點解大家都down兩次? XD [/quote]
hHr0KT/K
,Rj2b:?!Wkg P Q 我第一次開睇左2秒就close 左:P:P
qb8nOzn D 之後DL (就变成第二次)

playbr2 發表於 2008-1-18 12:34 AM

[quote]Originally posted by [i]sakura310[/i] at  12:27 AM: TQ}];]ev:k
Filename: DSC01158.JPGs2s1B$mii,ZZg8V-Jg
Datetime | Downloaded by | Countsq'Djde:E
2008-01-18 00:25:24 | 阿感 | 2-W6M V;M jJVZ
2008-01-18 00:24:20 | playbr2 | 2
C T3_8eCx 2008-01-18 00:22:02 | 但丁 | 2
V7g(Y a7Fm0hTu.W 7V uRr3m9CpJ x
點解大家都down兩次? XD [/quote]
5m Di0@ s4dJQ
_bF i?c'p 快d捉我錯處:D:D:D
[7o f#u(WU ? 話吾定我都打錯 + - 符號VG,~:Z(Ey.`
係電腦打答案...的確幾煩...又哂時間...:giveup:

sakura310 發表於 2008-1-18 06:47 AM

捉錯處就唔敢當"m4X+eq*k.WN
不過,c=101n哥度(解除n係正整數的限制,只是整數)
U0Z2@{$Cr6@zn 就一下子限制左c一定要係101的倍數(好像看懸疑片,突然劇情說出一些事前沒提及過的線索,不爽~)P'U0m~GR
知道{101,0,0}和{5151,2550,5050}係答案的話,當然沒問題
%[+p%`3{+I 但原先是不知答案,所以唔知有無失根;Z&[#|;F9X
tM"P)p ALE
有時見到題目都感到有點不爽:Lmc&MB8?c
題目所求的答案是整數,正整數,有理數,實數等等應該說清楚3?6b.~.M#Z%z.sx9T
有些題目,整數解和正整數解分別好大的說,要找出整數解集有時可不是件易事= =

cutec 發表於 2008-1-18 08:26 AM

冇答案ga....
6GTW1S;~p-S ]
.{'B B%vK)F 2條equation solve 唔到3個unknown ga....

Azuma 發表於 2008-1-18 08:56 AM

[quote]Originally posted by [i]cutec[/i] at 2008-1-18 08:26 AM:b,d3J ov4_ f XT
冇答案ga....
ym4E L)ny
{X[X#X-o\&{ L 2條equation solve 唔到3個unknown ga.... [/quote]#w4MNb}S!Jf^
:@!_u-h.zD q
agree QG8m{j].L
;z0k(y)Ia.Wp&X
2 equations 2 unknows
Z,vU1i2B He0}y @J-@2`O7E+vg6Lt
if 3 unknows there should be 3 equations
I"IGaW-@7t
f U({p2OCb make it simple
}2~2[k%h3`:CH 6ofu t l"Ms#U+c]
say (xd/Pq6W)[

LQ8Gy j4FR%a a + b +c = 3tpVhbt(]

7jP]3dF(E2Ok a+b = 2T H3i3sd)x*] A
!C-X$Cl K:yWJ
then c is 1 IgV"Q z$MM*C
qR9\,OF5V
a = 2 - b
!}[O;R*t7x .c)_#iB\?2{ O
so 0 = 0 uk W!g2J:V/X9Qd ~

'}/fd LN&\/B!H:v|V :giveup:

sakura310 發表於 2008-1-18 10:22 AM

[quote]Originally posted by [i]cutec[/i] at 2008-1-18 08:26 AM:
4CAnF{5Hj2K"I 冇答案ga....
$FR!|/?*OYQ_
irF|E9M4{'| 2條equation solve 唔到3個unknown ga.... [/quote]
(p$}Z9l OU.H ,G4Rj$v4p
此言差矣~
@Wyi%G/}9N
iI|eU)b 2條equation solve 唔到3個unknown ga){4Ltn l(^r7]V
還欠一個條件,就是3條equation都是linear independent(線性無關)的
H \QA8GtH%z
/Z*Me fb/b 簡單點說,多元一次方程就是線性方程的一個例子4Ig*~0O Ta
在這情況下,當然是想求n個未知數,至少要用n條線性無關的方程8V,d'mM? Ab%L8m
,vW!jUfd(^9U%b0N
如果不是線性的話,有機會1條方程解3個未知數的(這不是每次都可以的啦~)
}DU WA Y 例如 x^2-2(x+8y)+17+4y^2+z^0.5=0 就只有唯一整數解1CxgHrC
有興趣就解解看:sleep:3s3{ Z8C4M0@&Pf;x
不懂的話就問playplay,佢會知答案:dev:

playbr2 發表於 2008-1-18 02:47 PM

[quote]Originally posted by [i]sakura310[/i] at  10:22 AM:
_)]4Sw"?
"i)p*OD,sdSR
.gr hk.K-lxC7J 不懂的話就問playplay,佢會知答案[/quote]3UQQ-Z*q R5v
"C+?r?"K'c
:cry::giveup::giveup::giveup::giveup:

playbr2 發表於 2008-1-18 02:57 PM

[quote]Originally posted by [i]sakura310[/i] at  06:47 AM:
i6zAYJ S3K 捉錯處就唔敢當 @X;B\6iuF0U|g&q
不過,c=101n哥度(解... [/quote]3]K{"S4wz"LH

6F }s_ \)| 都係睇餸食飯姐 , 無理由因為題目冇同你假設就下下大包圍架
!XNuUfEG 反而適當地調節一下 , 咁會理性好多
T(s2o/D)rN 就好似隻game 由12粒珠 加到13粒珠咁qy&[Jr8b7n7p ] X'ed
當''堂''好玩哂:P:P:P-ue8[ d$@kD9s

%SH|5ZzboC0v&a4~&z p.s. 求''堂''字正寫:agree::giveup:

QuiGonJinn 發表於 2008-1-19 03:49 AM

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