如果我由北極轉穿個地下, 會唔會有一日到達南極?

spector.R

忽然有個奇想...你地有冇諗過
0 H6 A& h3 z% D/ @
3 L2 A  y9 {6 O" H假設我有一部能夠抵受地球中心熔岩熱力6650°C的轉地機, 唔知我可唔可以坐住佢轉入地下轉到去南極呢?
8 F+ V8 l- m8 P, f% v5 ~
$ ^! v/ S! t( H我諗其中一個難題係當我轉到去地球中心較下位置既時候可能會比地球既地心吸力吸反上去....除非加火箭推進器...
! K* X& H& s; Z  y9 P# ~; p/ {  Q* i- B! O( p3 D+ E
仲有一個假設係如果北極同南極係相通既(有條地底隧道)...  咁我由北極跳落去會發生咩事呢? 我諗就係當跌到落去地球中心我就會永遠停留係中心.... 唔上唔落...6 ^3 _: J' Y& g' u

0 a$ s# X9 R: Y4 }& G8 G地心吸力真係好神奇..../ P+ ^# a0 E9 p- P  \0 P7 k
http://i9.photobucket.com/albums/a86/kimsuna/complex2/earth3.jpghttp://i9.photobucket.com/albums/a86/kimsuna/complex2/earth1.jpg

cwleung1988

當你由北極轉穿個地下...首先應該會係世界未日左先喎 >,<

edwinycl

唔會啦肯定
* U" q! m; N4 G地心吸力係向內吸而唔係向下2 h. }2 g% ?- ~. |0 s9 Y8 d# a
當你到達地球核心o個陣就會停左到....郁都郁唔到

seafireson2

如果北極有個洞真穿南極,
4 b4 h: s+ f$ i: a5 p6 x0 n0 D  b您跌入去,- p" @" w. q5 P6 S- x. b) V% V
您會去到達南極~
# \; k5 Q! E9 w" ~; Z3 x6 B但到達南極後會吸回北極~~~
6 v6 L. H# u9 A6 K* j4 z到北極後又會吸回南極................$ r+ s" X, u# Q; ^/ B* ^
即係好像彈簧0甘~~~( N( ?4 g3 h' r" t% h! S0 m3 z& V6 C' r
(假設地球質量是平衡分佈)
0 _# D  D0 A0 Y) C(answer 來自我的預科物理ar sir)
& `/ v2 C, u  ]  J  w* H! |) |, v. B
事實上,地球質量是唔平衡分佈,; u# ?# e# u& }, T" L
so 一次反彈的力量會比一次少,  y+ j5 {% P( a  Q. d0 k
then 一次反彈的距離會比一次少
% E9 n& V! |0 \& F0 V% g8 U最後您會停在地心......% `6 _5 V! w( U% A
7 C/ J: H' T) P4 R, i9 Q
[ Last edited by seafireson2 on 2006-5-8 at 11:05 PM ]

milk~~

Originally posted by seafireson2 at 2006-5-8 10:24 PM:7 f+ s; Z, @8 m! D! I  G1 r
如果北極有個洞真穿南極, ' _9 b# O: M2 e3 U: Q' l0 f
您跌入去,...

, o% j% ?( C1 N* C: i7 ?$ b! x

& {' ~9 n# H0 C+ Y+ h對~~!5 {2 S1 r! q9 T
simple harmonic motion

fung

Originally posted by milk~~ at 2006-5-8 10:38 PM:3 w/ Q( l- z- I1 k" z# e9 c
, N% M. C0 B1 g# \" k: R( }
" Z/ z/ K; R+ e
對~~!6 c- D2 _& ^+ a* M
simple harmonic motion

: b2 B+ g% ^, h& ]$ {  J/ q: F! k; B8 e" Q# C+ I
仲要with damping

gaye

Originally posted by fung at 2006-5-8 11:22 PM:
) A4 t$ i% z9 F1 Y! k
. H* h7 c5 j: [/ ]3 I
" p& U# H$ Y& P9 W- S( z0 F+ P仲要with damping

. H( R# d2 o1 N$ i3 b2 ]$ N7 A
  O% }0 k+ N+ D$ D. _  h) w5 ?' I
但假如我唔係 North Pole jump 落去 , 係慢慢爬落去 , 咁到達地心時 , 再向 South Pole 出發個時, 係爬上去定爬落去 ?
$ p/ Y4 Y% t/ s, f. u0 E% J$ \/ w6 n% P. M* X' k  E! X
[ Last edited by gaye on 2006-5-8 at 11:36 PM ]

fung

Originally posted by gaye at 2006-5-8 11:35 PM:: o- @$ N1 E. p
' G0 s  z( Q8 H% x) o1 W7 ?
" ~/ ^  |; n% T7 g# E  i
但假如我唔係 North Pole jump 落...

3 I' n1 Z, T2 y( r. l
$ }5 a' V3 O- @' X+ N  U

/ _7 y6 }6 Y7 X+ _" w  ]9 H$ C- m* _
咁我諗要睇你點define上同落
/ @+ a; w- y0 j( G  u+ D
2 W7 X- K1 m% m5 `7 V3 z, Z7 D好似好廢...
$ N7 G; y! m9 w. O' X" k' v8 Y) O& b
, g# Q/ n3 m' }) f- L0 D

. R; l) _' ?( y8 G' v' q即係話如果你設由north -> south為落: \% I8 G9 [% b' \7 _1 b
由core去到south, 對north而言依然叫落
+ ?/ I; l/ s( _- H; h" |! {vice versa
, G- J& w5 {& b, h
6 k8 w; ?8 A5 y# E2 |: v( \- w9 H0 K! k% X& H: h5 W0 b
反而有樣野你要bear in mind ge係
: y0 K# j/ w* [  J8 ^( N由core出發, 要input energy

seafireson2

Originally posted by gaye at 2006-5-8 11:35 PM:# v' F! z+ K# _3 e; o+ B

; ]0 F  Z4 O1 _5 \% T4 I. z
# ^$ X) b8 s0 B  a0 I* Y但假如我唔係 North Pole jump 落...

6 t/ s7 r& O" T, Z1 C....................==""  Y. R; b' O3 y3 V
爬上去定爬落去係相對...............0 h( k* q: f; ]0 ]% H
個方向係由您set......
$ ~+ t" q) L- G0 Q3 H您定義north pole 係上面,0甘咪爬落law...3 U6 P& @: \1 V% e
您定義south pole 係上面,0甘咪爬上law...) l: Y# P. [4 }% V- u8 \1 x

  U( i- J. _( o1 m& Q+ N9 |however,點解唔simple d 呢........0 A5 a! y( b% y* p* y0 x! q- r
由地心去south pole,
$ L3 D. Q, l/ j& r0 ]& F# M& n0甘咪ok law..........

機密

Originally posted by spector.R at 2006-5-8 20:51:
7 W4 [# M1 J4 ?) L' ^忽然有個奇想...你地有冇諗過
- ?2 P* m) @4 h' X3 V
* A  T4 C' V% T1 \- {1 r/ V8 K假設...

+ I  P, S" A0 H  A, q
無乜可能，除了極熱之外，還要頂得住地心的高壓！ 未到對面你都變左屎餅啦！ 瓜！