| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎
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(x - a) = x - a
" p$ Q1 L1 d' _/ G" R(x - a) (x - b) = x^2 – ax – bx + ab
& e9 N! W/ z) {/ ~  w& y/ Y; x(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc
) K9 g. a2 G; u: m5 S0 }1 R7 Y(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd
/ d3 E* T1 g$ @/ Q如此種推，- T* p  L1 ?8 p' ^8 T1 T% W9 f
(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???  T4 X* i( E. o6 j( ]$ f9 E- w

3 `+ a' W, _* ?) f" r1 W. V3 c[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

大大

點解你個問題好似有d問題3 D. u8 X  X/ V2 ~' T

Originally posted by Triangel at 2007-4-18 01:26 PM:5 D+ `* F3 C/ g% h% _
(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 – abx + acx + bcx - abc. Q3 g- J& @) ]9 @
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[ Last edited by 大大 on 2007-4-18 at 01:54 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:
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[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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, r4 k& ]# R& ^5 U4 x$ CThanks! 更正啦

littlenic

Originally posted by Triangel at 2007-4-18 01:26 PM:! ^. s1 O- S3 Y
第一個答中有獎' G: T- X) T, e; a. J) L

% B9 Y" l( m$ ^8 J$ l. C* X0 d(x - ...

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(x-x)= 0 ，所以答案係0，is it?

大大

Originally posted by littlenic at 2007-4-18 01:54 PM:
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4 k* p2 ~; m, B( }5 M2 [. U0 q(x-x)= 0 ，所以答案係0，is it?

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唔似a.math題
/ b6 V- Y% L, t- T! T似IQ題=.=% \* `/ W! I) K2 t, O6 j

, Z5 I$ \5 C6 F# j5 d' `* ?[ Last edited by 大大 on 2007-4-18 at 01:57 PM ]

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:
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* |" U" m1 w; _1 W2 m3 d(x-x)= 0 ，所以答案係0，is it?

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- E' T* I! _. {2 GBingo~

waikong

我係學校個學生會單張見過
3 s+ F/ t  M. P0 Q! t6 j諗左一陣先諗到

playbr2

我吾識答啊http://i72.photobucket.com/albums/i162/xcopy/Monkey/049.gif~~~ http://i72.photobucket.com/albums/i162/xcopy/Monkey/022.gif

karen0123

(哭)~~~~~其實我都知係0.........
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這條問題，貼落吹水版，名副其實
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[ Last edited by karen0123 on 2007-4-18 at 05:51 PM ]