| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎7 y* g6 {) f4 n- t2 k/ L- a
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(x - a) = x - a. B( I0 z, g& J8 V
(x - a) (x - b) = x^2 – ax – bx + ab4 w$ j8 ?$ K! A' Y7 p
(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc7 @7 i8 x# a1 H
(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd4 Z0 @0 q5 D+ H
如此種推，
6 o# w8 C+ ]' f& ?(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???( J- r6 g- a" U# N) L9 z0 X# M, X! C
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[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

大大

點解你個問題好似有d問題7 O% s5 ^2 \8 s4 u5 _* D7 e+ N% \8 q

Originally posted by Triangel at 2007-4-18 01:26 PM:
7 y* V% [) }7 ~% h/ M) u(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 – abx + acx + bcx - abc
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[ Last edited by 大大 on 2007-4-18 at 01:54 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:9 C  N5 p! M; [, u
咁難既=.="
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8 r1 C3 l. F# U[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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( X9 t; x/ M% ~Thanks! 更正啦

littlenic

Originally posted by Triangel at 2007-4-18 01:26 PM:
/ S4 K9 m5 @* }* R/ B; ^第一個答中有獎
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5 U9 Z- ~- _3 X  }' u(x - ...

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) b, [3 g8 A- P! ~, b(x-x)= 0 ，所以答案係0，is it?

大大

Originally posted by littlenic at 2007-4-18 01:54 PM:
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4 M$ @$ W+ S$ M  g6 p& t(x-x)= 0 ，所以答案係0，is it?

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唔似a.math題/ R9 M& O8 \0 u: g: a5 v# B
似IQ題=.=2 w: \* Y! X, W0 R- ?1 w

: ~. k0 F, W2 q$ h, k5 q7 A[ Last edited by 大大 on 2007-4-18 at 01:57 PM ]

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:
$ ~$ P, S  I0 F3 Y, a- T0 U' N" W# m# \4 ~8 S8 V. P

$ k6 G& R; F; d; `. O" _- `(x-x)= 0 ，所以答案係0，is it?

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Bingo~

waikong

我係學校個學生會單張見過, a" y& v9 ~$ s" E% k* U
諗左一陣先諗到

playbr2

我吾識答啊http://i72.photobucket.com/albums/i162/xcopy/Monkey/049.gif~~~ http://i72.photobucket.com/albums/i162/xcopy/Monkey/022.gif

karen0123

(哭)~~~~~其實我都知係0.........
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8 [0 v, K! F8 A6 s這條問題，貼落吹水版，名副其實6 E- b% L& l7 {3 O' Y* J0 R$ ~
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[ Last edited by karen0123 on 2007-4-18 at 05:51 PM ]