seafireson2

如果北極有個洞真穿南極,
5 K1 m- M6 F0 A% M  ~' i您跌入去,
$ }6 y9 c- B4 }: R" P" m6 X& {您會去到達南極~' \6 u  `& ~/ s7 \6 n
但到達南極後會吸回北極~~~: E$ S; O: x0 Q
到北極後又會吸回南極................3 k( o8 E! V: H+ P8 G
即係好像彈簧0甘~~~
+ c% s4 D; s! p4 K4 x6 L(假設地球質量是平衡分佈)2 |  p: g8 w5 l
(answer 來自我的預科物理ar sir)
3 c/ u1 Q6 w, L4 q4 {& F  F* P& N' t/ x7 }. _% }" w( u5 c, d
事實上,地球質量是唔平衡分佈,
3 P; V- M; h( g. [1 ]# H3 Kso 一次反彈的力量會比一次少," B) c" y# O, T- j" ]2 N
then 一次反彈的距離會比一次少
2 q. w8 {/ W! W' r1 }4 Y5 _最後您會停在地心....... H$ m  l9 F- B) M
9 Q0 ^' Z7 c0 Y
[ Last edited by seafireson2 on 2006-5-8 at 11:05 PM ]

seafireson2

Originally posted by gaye at 2006-5-8 11:35 PM:& z. i  h: H: `, F: g
% D& t) |  t% H/ s! a

; B- V) F) s) P, ?" c: y' T. F4 {. e但假如我唔係 North Pole jump 落...

( @4 H; f, S: U" O' g
....................==""6 u$ P& I/ V& O2 S- |
爬上去定爬落去係相對...............3 g3 N4 S6 x+ O3 W) Q
個方向係由您set......
3 H9 \  Q$ q0 R- Y; b1 Z您定義north pole 係上面,0甘咪爬落law...7 y$ A) \" ?2 ]1 W: J& E4 C
您定義south pole 係上面,0甘咪爬上law...
; a8 B+ a& [  ~9 V! T! X! S$ n! `# D/ y/ A7 m0 t6 _& h+ X
however,點解唔simple d 呢........
+ a  R* U: f/ @8 j由地心去south pole,
$ A) J; x' E* n! t9 z6 g0甘咪ok law..........

seafireson2

Originally posted by 機密 at 2006-5-9 12:10 AM:6 f+ e; R/ X! W5 h

' _% h' [1 }3 \8 ~& l/ l6 g# b無乜可能，除了極熱之外，還要頂得住地心的高壓！ 未到對面你都變左屎餅啦！ 瓜！

" Y- {5 M! |! ?# A
都話明"假設"ar!!!!!!假設唔一定要正確ga.............

seafireson2

Originally posted by FishyR at 2006-5-9 05:09 PM:
! p# @6 h& @8 s, W6 R我結論係去唔到最中心, 而喺地心同地面之間停下來. 喺個點係無地心吸力, 因地面質量對我所做成o既萬有引力, 同地心質量對我所做成o既萬有引力喺對等.

5 S+ R# r# Z  X0 u其實係去到地心,南北半球ge地心吸力先相等同抵消~so地心ga引力係0~~~~" R# M( A; m2 M) ^  Z- z( W4 L" V
但您之前有加速,即您本身有speed~0甘您會直去,但去南半球時又受引力,會減speed,最後係南半球表面stop~~~