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36#
發表於 2007-3-14 09:45 PM
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我認為總之去到最尾,中唔中都只係1/2機會
所謂D1/3,2/3嘅機會率,只係响個主持開嗰度沒有車嘅門之前出現,once佢開咗度無車嘅房門,由於個condition唔同咗,所以要計個參賽者贏架車嘅機會率又唔同咗嘞!
响計probability入便,condition好緊要,要define 得清楚,condition 轉咗的話,(in this case:開咗一間冇車的房門),又要「重新」因應新condition計過個機會率嘞!
(其實仲有condition on condition 嘅case,要計埋set同subset嘅嘢,但唔想太煩)
其實我估個女天才所引用嘅道理係:
我開頭揀咗一度門,而架車响度門後面嘅機會係三分之一,架車响另外兩度門後面嘅機會「加埋」係三分之二(1/3+1/3),而當主持開咗一度冇車嘅門之後,由於嗰度門有車嘅機會率而家發現係零,所以响原本嗰兩度門後面有車而架車而家响淨低另一度門後面嘅機會率就係:
2/3 -- 0 = 2/3
that's why she insist to change her choice to the other door cos 2/3 is greater than 1/3. |
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