| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎
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- R2 c" p5 z1 O  [- z/ u/ N& T(x - a) = x - a
. N$ u; m9 b; b(x - a) (x - b) = x^2 – ax – bx + ab+ j: _4 E6 j: y
(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc
0 k* R! A7 v8 l* {( |. S! X" g(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd
. {' S1 P+ d9 ^! D1 \0 I如此種推，
2 B- ~- N) P7 Z* {# i9 O8 ]7 A. W(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???
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[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:$ o* z2 F0 ~( h4 ]4 v4 Q
咁難既=.="  G. ]' a4 T6 m$ m/ J8 `$ ]4 i6 b: O

# [+ c& U2 I& s, Q[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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3 ^/ \: l# B! J. Q0 g! }0 ^Thanks! 更正啦

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:
* h9 u6 a' U& L
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% i: Y$ x8 C0 n% t% e# P9 P6 R(x-x)= 0 ，所以答案係0，is it?

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Bingo~