| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎/ I6 F/ d1 T& c8 v6 t, o; J

4 m! D. P0 K% t/ }& l(x - a) = x - a
: o# s+ u! m2 k+ l) Z$ K5 @- q! u(x - a) (x - b) = x^2 – ax – bx + ab
1 Y' A% _# F5 X  A+ a, [* m' C(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc3 ^9 y3 t' j. t4 y
(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd9 F9 H: B% z) M2 t5 P: d6 \
如此種推，7 y5 M+ t6 T! N& a/ _4 ]% n0 b
(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???
7 j2 c$ k' C3 [, |! g! b$ n2 o" x) n: V% b# p$ N
[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:0 s: b4 \, f: p6 A
咁難既=.="
7 s) A4 e) X1 Q& i* ~7 t* v7 j9 T/ o
[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

* b4 j# c% K; u: s$ s' ?+ |$ s8 G/ m0 z% r
Thanks! 更正啦

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:4 y/ }: M3 ], K8 b1 P$ [% G' y

9 Q: `/ u# W! b+ _- B4 H* j& u
, b2 s- u" w; t0 B# e; i; D0 A(x-x)= 0 ，所以答案係0，is it?

) ^' [7 k5 ]5 B$ Z! N! z3 ~# I

7 i6 R4 o2 t/ G  ^6 [0 IBingo~