| TriTri | A-Math 加分題 |

Triangel

第一個答中有獎8 }  U  M6 w5 k6 O+ _( x1 P4 G
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(x - a) = x - a
! h. ^& g/ ^: _6 A; G(x - a) (x - b) = x^2 – ax – bx + ab
/ n# F/ ~* b/ l3 f! ?0 n. y5 P4 j0 R(x - a) (x - b) (x – c) =  x^3 – ax^2 – bx^2 – cx^2 + abx + acx + bcx - abc& a1 x% _0 p. M9 d3 U4 {' j. U) E
(x - a) (x - b) (x – c) (x - d) = x^4 – ax^3 – bx^3 – cx^3 – abx^2……………….. +abcd! s7 y* @0 ~! G, u* }
如此種推，
2 m. k# s  m* I6 r(x-a) (x-b) (x-c) (x-d) (x-e)……..(x-z) = ???6 X3 \. }: `, Y/ B

! ~' E+ u8 ]1 f3 ?* l[ Last edited by Triangel on 2007-4-18 at 01:52 PM ]

Triangel

Originally posted by 大大 at 2007-4-18 01:41 PM:6 J% L4 Q: E: g$ h0 Y; ~# N  _
咁難既=.="
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: g& C/ R6 a2 _  |, i# `$ ^[ Last edited by 大大 on 2007-4-18 at 01:52 PM ]

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Thanks! 更正啦

Triangel

Originally posted by littlenic at 2007-4-18 01:54 PM:
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  @$ o6 Z7 X' z7 N( _
  u6 @7 F& U) E(x-x)= 0 ，所以答案係0，is it?

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5 p$ v; q1 K9 v; sBingo~